【发布时间】:2013-12-06 07:52:00
【问题描述】:
我想使用 JPA 调用 Oracle 函数。我在这个话题上找到了this thread。
但我的 Oracle 函数只返回一个字符串。不是某种实体的结果。我试过这样的事情:
@NamedNativeQuery(name = "myFuncCall",
resultSetMapping = "myResultSetMapping",
query = "{ ? = call schema.mypkg.somefunc(:id) }",
hints = { @javax.persistence.QueryHint(name = "org.hibernate.callable", value = "true") }
)
@SqlResultSetMapping(name = "myResultSetMapping",
columns = { @ColumnResult(name="somename") }
)
当我这样调用查询时
Query query = em.createNamedQuery("myFuncCall", String.class).setParameter("id", "42");
String res = (String) query.getSingleResult();
我明白了
Hibernate: { ? = call schema.somefunc(?) }
18:21:11.222 [main] WARN o.h.util.JDBCExceptionReporter - SQL Error: 6550, SQLState: 65000
18:21:11.222 [main] ERROR o.h.util.JDBCExceptionReporter - ORA-06550: Row 1, Column 13:
PLS-00382: This expression has the wrong type
ORA-06550: Row 1, Column 7:
PL/SQL: Statement ignored
javax.persistence.PersistenceException: org.hibernate.exception.SQLGrammarException: could not execute query
at org.hibernate.ejb.AbstractEntityManagerImpl.convert(AbstractEntityManagerImpl.java:1389)
at org.hibernate.ejb.AbstractEntityManagerImpl.convert(AbstractEntityManagerImpl.java:1317)
at org.hibernate.ejb.QueryImpl.getSingleResult(QueryImpl.java:307)
有什么想法吗?
【问题讨论】:
-
你有没有找到任何对这个有用的东西,我也一起破解了其他东西
-
不,还是和下面一样,很遗憾。