【发布时间】:2018-04-23 14:35:14
【问题描述】:
我在调用 oracle 函数时遇到问题, 函数如下所示
CREATE OR REPLACE FUNCTION get_port_out_select
(pi_id_pout_order IN PORT_OUT_ORDER.ID_POUT_ORDER % TYPE)
RETURN sys_refcursor
IS
lc_cursor sys_refcursor;
BEGIN
OPEN lc_cursor FOR
SELECT ID_POUT_ORDER, ID_LEC_USER, ID_POUT_LEC, ID_SERVICE_REC, POUT_TN, ID_IPTN, POUT_LEC_OCN, POUT_LEC_SPID, POUT_ALI_CODE,
LEC_CONTACT_FNAME, LEC_CONTACT_LNAME, LEC_CONTACT_TN, LEC_CONTACT_EMAIL,
DL_LEC_OCN, CUST_ACCT, CUST_F_NAME, CUST_L_NAME,
SVC_ADDR_STR, SVC_ADDR_NUM, SVC_ADDR_CITY, SVC_ADDR_STATE, SVC_ADDR_ZIP,
POUT_LOA_DATE, POUT_DDD, POUT_FOC, E_MAIL_SENT_DATE, V_MAIL_SENT_DATE, ID_POUT_STATUS, CUSTOMER_TYPE, AUTHORIZATION_NAME, ID_MASTER_POUT_ORDER
FROM PORT_OUT_ORDER
WHERE ID_POUT_ORDER = pi_id_pout_order
AND ID_POUT_STATUS < 95;
RETURN lc_cursor;
END;
它以光标的形式返回值 Bellow 是我在 DB 中执行查询时的结果。
{<
ID_POUT_ORDER=2004,
ID_LEC_USER=39,
ID_POUT_LEC=36,
ID_SERVICE_REC=20277159,
POUT_TN=7186846814,
ID_IPTN=3990,
POUT_LEC_OCN=9147,
POUT_LEC_SPID=9147,
POUT_ALI_CODE=9147,
LEC_CONTACT_FNAME=unique,
LEC_CONTACT_LNAME=user,
LEC_CONTACT_TN=5165551234,
LEC_CONTACT_EMAIL=michael21474@gmail.com,
DL_LEC_OCN=9147,
CUST_ACCT=0785852664101,
CUST_F_NAME=YYYYYYY,
CUST_L_NAME=ZZZZZZ,
SVC_ADDR_STR=10thav,
SVC_ADDR_NUM=812,
SVC_ADDR_CITY=levittown,
SVC_ADDR_STATE=NY,
SVC_ADDR_ZIP=11756,
POUT_LOA_DATE=11-APR-07,
POUT_DDD=11-APR-07,
POUT_FOC=11-APR-07,
E_MAIL_SENT_DATE=10-APR-07,
V_MAIL_SENT_DATE=null,
ID_POUT_STATUS=1,
CUSTOMER_TYPE=Residential,
AUTHORIZATION_NAME=unique user,
ID_MASTER_POUT_ORDER=null
>,
}
Query query = this.em.createNativeQuery("SELECT get_port_out_select(2004) FROM DUAL");
query.getSingleResult();
我在获取结果时遇到问题。 我检查了与数据库的连接一切都很好。 我该如何处理
更新 1:
创建实体类
@NamedNativeQueries(value = {
@NamedNativeQuery(
name = "functionCall",
query = "{ SELECT get_port_out_select(2004) FROM DUAL }",
resultClass = PortOutSelectCursor.class)
})
@Entity
public class PortOutSelectCursor{
@Id
@Column(name="ID_POUT_ORDER")
private int ID_POUT_ORDER;
@Column(name="ID_LEC_USER")
private int ID_LEC_USER;
@Column(name="ID_SERVICE_REC")
private int ID_SERVICE_REC;
@Column(name="POUT_TN")
private String POUT_TN;
@Column(name="ID_IPTN")
private int ID_IPTN;
// added all the attribute
// added default constructor
// added setter and getter
}
在persistence.xml中添加了映射
<persistence-unit name="XOSS_PDB_PROCEDURE_PERSISTENCE_UNIT_1"
transaction-type="JTA">
<provider>org.hibernate.jpa.HibernatePersistenceProvider</provider>
<jta-data-source>myDataSource</jta-data-source>
<mapping-file>META-INF/procedure.xml</mapping-file>
<class>com.amdocs.oss.alt.procedure.response.PortOutSelectCursor</class>
<properties>
<property name="javax.persistence.jdbc.driver" value="oracle.jdbc.driver.OracleDriver" />
<property name="hibernate.show_sql" value="true" />
<property name="hibernate.format_sql" value="true" />
<property name="hibernate.dialect" value="org.hibernate.dialect.Oracle10gDialect" />
<property name="hibernate.hbm2ddl.auto" value="none" />
<property name="hibernate.transaction.jta.platform"
value="org.hibernate.service.jta.platform.internal.WeblogicJtaPlatform" />
<property name="hibernate.proc.param_null_passing" value="true" />
<property name="alt.procedure_names" value="insertEquipReturn,getPortOutSelect" />
<property name="hibernate.archive.autodetection" value="class"/>
</properties>
</persistence-unit>
道类是这样的
public void getPortOutSelect() {
try {
List < Object[] > a = this.em.createNamedQuery("functionCall").getResultList();
Object[] r = a.get(0);
} catch (Exception e) {
e.printStackTrace();
}
return null;
}
仍在努力解决问题。请帮忙
【问题讨论】:
-
ORA-22905:无法访问非嵌套表项 22905 中的行。 00000 - “无法访问非嵌套表项中的行” *原因:尝试访问类型为在解析时未知或不是嵌套表类型 *操作:使用 CAST 将项目转换为嵌套表类型 行错误:5 列:14
-
当我这样做时
SELECT get_port_out_select(2004) FROM DUAL我得到了上面提到的结果 -
这意味着错误出在Java而不是oracle的某个地方。
-
我只是更新问题,我到目前为止所尝试的
-
请同时添加您遇到的所有错误
标签: java hibernate jpa oracle10g