【发布时间】:2020-07-02 09:47:39
【问题描述】:
我在以下 2 个实体之间存在一对一的关系:
@Entity
@Table(name = "user")
public class User {
@Id
@Column(name="id")
private String id;
@Column
private String name;
@Column
private String email;
@Column
private String password;
@OneToOne(cascade = CascadeType.PERSIST, fetch = FetchType.EAGER)
@JoinColumn(name = "user_role_id", referencedColumnName = "id")
private UserRole userRole;
@Entity
@Table(name = "userRole")
public class UserRole {
@Id
@Column(name="id")
private String id;
@Column
private String description;
@OneToOne(mappedBy = "userRole")
private User user;
public UserRole() {
}
我还使用 EntityManagerFactory 在本地数据库中创建表。我收到了这个代码,我必须遵循它。
public class UserRepo {
private EntityManagerFactory entityManagerFactory = Persistence.createEntityManagerFactory("ro.tutorial.lab.SD");
public void insertNewUser(User user) {
EntityManager em = entityManagerFactory.createEntityManager();
em.getTransaction().begin();
em.persist(user);
em.getTransaction().commit();
em.close();
}
也有类似的 UserRoleRepo。
我的问题是在 main 中实例化时,我不知道如何仅获取 User 中 FK 的 UserRole id。相反,我得到了 userRole 的整个实例和错误“重复条目 'b36fcb4c-3904-4205-888b-9792f24d8b5c' for key 'userrole.PRIMARY'”。
public static void main(String[] args) {
UserRoleRepo userRoleRepo= new UserRoleRepo();
UserRole userRole1 = new UserRole();
userRole1.setId(UUID.randomUUID().toString());
System.out.println(userRole1);
userRole1.setDescription("admin");
userRoleRepo.insertNewUser(userRole1);
UserRole userRole2 = new UserRole();
userRole2.setId(UUID.randomUUID().toString());
System.out.println(userRole2);
userRole2.setDescription("client");
userRoleRepo.insertNewUser(userRole2);
UserRepo userRepo= new UserRepo();
User user = new User();
user.setId(UUID.randomUUID().toString());
user.setName("Todoran");
user.setEmail("todoran@utcluj.ro");
user.setPassword("mona");
user.setUserRole(userRole1); //////////it breaks here :(((((
System.out.println(user);
userRepo.insertNewUser(user);
}
【问题讨论】:
标签: java hibernate foreign-keys persistence.xml hibernate-entitymanager