特定整数的while循环（Python）

Question

所以我使用 Python 中的 randint() 函数随机生成了 2 个数字。假设这些数字是 x1 和 x2。游戏玩家必须猜测这些数字的除法值，并给出一个偏差，这意味着猜测与正确答案相差多少百分比。数字变得越来越困难。

现在我有一个 while 循环（正确答案 = x1 // x2）：

print(int(input("Guess: ")))
  while guess != correct_answer or guess == correct_answer:
    print(f"{deviation}, next numbers: {x1}, {x2}") 
    print(int(input("Insert your guess: ")))
    print(f"{deviation}, next numbers: {x1}, {x2}")  #i want to change the difficulty here
    break

我可以简单地写 x1 + number 来改变 x1 的值并使其更困难，但偏差仍然与第一个难度使用的偏差相同。我不知道如何通过尝试的不同难度来改变偏差。 偏差百分比写为(guess - correct_answer)*100

Answer 1

据我了解，这就是您要创建的内容：

import random

for i in range(5):
    x1, x2 = sorted(random.choices(range(1, 10 ** (i + 1)), k=2), reverse=True)
    print(f'Guess the result of FLOOR division of the following numbers:\n'
          f'{x1} and {x2} ({x1} divided by {x2})')
    guess = int(input('Your guess: '))
    result = x1 // x2
    if guess == result:
        print('You guessed correctly!\n')
        continue
    deviation = abs((guess - result) / result) * 100
    print(f'Your answer was {deviation: .0f}% away from the correct answer of {result}\n')

难度越来越大的楼分猜测者，也能说出与正确答案的偏差。

要简单地对抗ZeroDivisionError，您可以添加以下内容：

try:
    deviation = abs((guess - result) / result) * 100
except ZeroDivisionError:
    deviation = 0

但更简单的方法是通过将 x1 排序为大于 x2 来简单地不让 result 为 0，如果使用 random.randint 可以这样做：

x1, x2 = sorted([random.randint(1, 10 ** (i + 1)), random.randint(1, 10 ** (i + 1))], reverse=True)

完整示例：

import random

tries = 5
user_stats = list()

for i in range(5):
    abs_range = 10 ** (i + 1)
    x1 = random.randint(-abs_range, abs_range)
    x2 = random.choice(list(range(-abs_range, 0)) + list(range(1, abs_range + 1)))
    print(f'Guess the result of FLOOR division of the following numbers:\n'
          f'{x1} and {x2} ({x1} divided by {x2})')

    user_stats.append(list())

    for j in range(tries):
        guess = int(input('Your guess: '))
        result = x1 // x2
        if guess == result:
            print('You guessed correctly!\n')
            user_stats[-1].append('Success')
            break
        deviation = (guess - result) / result * 100 if result != 0 else 0
        print(f'Your answer was {deviation: .0f}% away from the correct answer\n')
        user_stats[-1].append((guess, deviation, j + 1))
    else:
        print('Game failed!')
        break

print(user_stats)

来源：

• sorting in Python
• random.choices