在while循环中计数/随机int

Question

我希望这个 while 循环在每次迭代时更改数字（包括计数和随机整数。）但是当我运行程序时，循环只会继续计数和随机整数上的相同数字。：

# if 4 sides 
die1 = random.randint(1,4)
die2 = random.randint(1,4)
count = 1 

while sides == 4 and die1 != die2:
    print (count, ". die number 1 is", die1, "and die number 2 is", die2,".")
    count == count + 1

print ("You got snake eyes! Finally! On try number", count,".")

Answer 1

您可以使用带有 iter 的 for 循环来吐出随机数对，enumerate 将进行计数，对于蛇眼，您还应该检查两者都是 1 不是随机匹配对：

from random import randint                                                                   

def repeating_rand(i, j):                                                                    
    for count, (r1, r2 ) in enumerate(iter(lambda: (randint(i, j), randint(i, j)), None), 1):
        if r1 == 1 and r2 == 1:                                                              
            return "You got snake eyes! Finally! On try number {}.".format(count)            
        print("Try no. {}, die number 1 is {} and die number 2 is {}".format(count, r1, r2)) 

输出：

 In [12]: repeating_rand(1, 4)
Try no. 1, die number 1 is 1 and die number 2 is 2
Try no. 2, die number 1 is 4 and die number 2 is 1
Try no. 3, die number 1 is 1 and die number 2 is 2
Try no. 4, die number 1 is 1 and die number 2 is 3
Try no. 5, die number 1 is 1 and die number 2 is 3
Try no. 6, die number 1 is 3 and die number 2 is 4
Try no. 7, die number 1 is 4 and die number 2 is 2
Try no. 8, die number 1 is 1 and die number 2 is 2
Try no. 9, die number 1 is 3 and die number 2 is 2
Try no. 10, die number 1 is 4 and die number 2 is 3
Try no. 11, die number 1 is 1 and die number 2 is 3
Try no. 12, die number 1 is 3 and die number 2 is 4
Out[12]: 'You got snake eyes! Finally! On try number 13.'

Answer 2

您还需要在while 循环内调用random，否则它们不会改变。另一件事是你比较==而不是设置=计数器：

import random

sides = 4
count = 1 
die1 = random.randint(1,4)
die2 = random.randint(1,4)

while sides == 4 and die1 != die2:
    print (count, ". die number 1 is", die1, "and die number 2 is", die2,".")
    count += 1
    die1 = random.randint(1,4)
    die2 = random.randint(1,4)

print ("You got snake eyes! Finally! On try number", count,".")

尝试测试运行给了我：

1 . die number 1 is 4 and die number 2 is 3 .
2 . die number 1 is 2 and die number 2 is 1 .
3 . die number 1 is 1 and die number 2 is 2 .
4 . die number 1 is 3 and die number 2 is 4 .
5 . die number 1 is 1 and die number 2 is 4 .
You got snake eyes! Finally! On try number 6 .

一种几乎相同但使用break而不是while循环中的条件的替代方法是：

import random

sides = 4
count = 1 

def tossdie():
    """Function to create a random integer for a die"""
    return random.randint(1,4)

while True:
    die1 = tossdie()
    die2 = tossdie()
    print (count, ". die number 1 is", die1, "and die number 2 is", die2,".")
    if die1 == die2:
        break
    count += 1

print ("You got snake eyes! Finally! On try number", count,".")

Answer 3

每次您调用random.randint(1,4)，您都在创建一个随机数。每当您打印它时，它都不会神奇地更改为新的随机数。

在while 循环中使用random.randint(1, 4) 生成新的随机数。

第二个问题是count == count + 1 检查是否相等（并在您的情况下返回False）。要进行赋值，请使用赋值运算符 = 或 count += 1 将 count 加一。

如果你想要一个无休止地输出随机数的生成器，写一个：

>>> import random
>>> def rng(i, j):
...     while True:
...         yield random.randint(i, j)
... 
>>> random_gen = rng(1, 4)
>>> next(random_gen)
2
>>> next(random_gen)
3
>>> next(random_gen)
2
>>> next(random_gen)
2
>>> next(random_gen)
1

Answer 4

不知道你为什么需要sides 变量，所以我把它省略了。 您想在每个循环中掷骰子，这意味着您必须在每个循环中将die1 和die2 重新分配给一个随机数。

import random

# Initial parameters
die1 = random.randint(1,4)
die2 = random.randint(1,4)
count = 1

# Loop and roll die each time
while die1 != die2:
    print(count, ". die number 1 is", die1, "and die number 2 is", die2,".")
    die1 = random.randint(1,4)
    die2 = random.randint(1,4)
    count += 1

# Print on which die roll you got two equal die numbers rolled
print ("You got snake eyes! Finally! On try number", count,".")