关于自制数字猜谜游戏的问题

Question

我从 2 天开始就在尝试学习 python，我正在通过这个网站上的这个小 python 项目挑战自己：https://www.upgrad.com/blog/python-projects-ideas-topics-beginners/#1_Mad_Libs_Generator

我现在在第二场比赛（猜数字游戏）。

指令如下：

'''制作一个程序，其中计算机随机选择一个介于 1 到 10、1 到 100 或 任何范围。然后给用户一个猜测数字的提示。每次用户猜错， 他得到了另一个线索，他的分数被降低了。线索可以是倍数的，可分的， 更大或更小，或所有的组合。 您还需要将输入的数字与猜测的数字进行比较的函数，以计算 两者之间的区别，并检查这个python项目中是否输入了实际数字。'''

import random

print("Welcome to the number game. A random number will be generated and you can guess which one it is.")
print("You got three tries.")

number = random.randint(1, 99)
guess = ""  # var to store users guess
guess_count = 0
guess_limit = 3
out_of_guesses = False

while guess != number and not out_of_guesses:
    if guess_count < guess_limit:
        guess = int(input("Enter a guess: "))
        guess_count += 1
        if guess < number:
            print("Your guess is too small. Try again.")
        elif guess > number:
            print("Your guess is too high. Try again.")
    else:
        out_of_guesses = True

if out_of_guesses:
    print("You are out of guesses. You loose!")
else:
    print("Your guess is correct. You Won!")

输出如下：

Welcome to the number game. A random number will be generated and you can guess which one it is.
You got three tries.
Enter a guess: 78
Your guess is too high. Try again.
Enter a guess: 28
Your guess is too small. Try again.
Enter a guess: 29
**Your guess is too small. Try again.**
You are out of guesses. You loose!

我的问题是标记为 strong 的行。实际上，在用户进入第三次尝试并没有猜到正确答案后，我不希望显示“你的猜测太……”这行。但是，在用户尝试完之前，我确实希望它显示出来。

您对如何调整代码有任何提示吗？

另外，我确实理解了 try 和 except 的概念，但真的不知道在哪里添加它以使游戏在输入错误的输入类型时更加“流畅”。

亲切的问候

Answer 1

鉴于当前的代码结构，您可以通过在guess 和number 比较中添加额外的检查来避免打印最后一次猜测的提示。

关于异常处理，程序的崩溃点涉及到用户输入与数字的比较。围绕用户输入的整数转换添加异常处理似乎是合适的。在增加 guess_count 和 continue 以允许其他用户输入之前执行此操作将允许游戏运行 3 个有效输入。

用于引用异常的_ 变量是一个“一次性”变量——这只是一个常规名称。然而，在解释会话中，_ 将存储先前执行的语句的返回值。

import random

print("Welcome to the number game. A random number will be generated and you can guess which one it is.")
print("You got three tries.")

number = random.randint(1, 99)
guess = ""  # var to store users guess
guess_count = 0
guess_limit = 3
out_of_guesses = False

while guess != number and not out_of_guesses:
    if guess_count < guess_limit:
        try:
            guess = int(input("Enter a guess: "))
        except ValueError as _:
            print('Wrong input type')
            continue
        guess_count += 1
        if guess < number and guess_count != guess_limit:
            print("Your guess is too small. Try again.")
        elif guess > number and guess_count != guess_limit:
            print("Your guess is too high. Try again.")
    else:
        out_of_guesses = True

if out_of_guesses:
    print("You are out of guesses. You lose!")
else:
    print("Your guess is correct. You Won!")