TypeError-'function' 对象不可迭代答案

【问题标题】：TypeError-'function' object is not iterableTypeError-'function' 对象不可迭代
【发布时间】：2016-07-31 16:01:17
【问题描述】：

我有一个程序，教师可以查看她学生的测验结果并以一种简单的方式对其进行排序：

if role == 2:
class_number = prompt_int_big("Which class' scores would you like to see? Press 1 for class 1, 2 for class 2 or 3 for class 3")
filename = (str(class_number) + "txt")
sort_or_not = prompt_int_small("Would youlike to sort these scores in any way? Press 1 if the answer is no or 2 if the answer is yes")
if sort_or_not == 1:
    f = open(filename, "r")
    lines = [line for line in f if line.strip()]
    lines.sort()
    for line in lines:
        print (line)
if sort_or_not == 2:
    type_of_sort = prompt_int_big("How would you like to sort these scores? Press 1 for scores in alphabetical order with each student's highest score for the tests, 2 if you would like to see the students' highest scores sorted from highest to lowest and 3 if you like to see these student's average scores sorted from highest to lowest")
    if type_of_sort == 1:
        with open(filename , 'r') as r:
            for line in sorted(r):
                print(line, end='')
    if type_of_sort == 2:
        with open (filename,'r') as r:
            def score(line):
                return int(line.split(':')[1])
            for line in sorted(r, key=score, reverse = True):
                print(line)
    if type_of_sort == 3:
        with open (filename,'r') as r:
            def score(line):
                returnint(line.split(':')[1])
            average = sum(map(int, score))/len(score)
            print(name,"--",average)

However when the third option is selected an error comes up:

average = sum(map(int, score))/len(score)
TypeError-'function' object is not iterable

【问题讨论】：

如果你要投反对票，至少说明原因
投反对票的意思是，当用户投反对票时，来自 SO 的确切引用：“这个问题没有任何研究工作，不清楚或没有用”。在这种情况下，我最好的建议是：请花点时间阅读Help center 中的提问指南。

标签： python-3.x random average typeerror

【解决方案1】：

map() 在 Python-3.x 中返回一个迭代器（与 Python-2.x 不同，它返回结果列表）。因此，您需要从迭代器生成列表，然后将其传递给sum() 函数。

average = sum(list(map(int, score)))/len(score)

在上面，示例score 应该是可迭代的，就像一个列表或一个元组。

编辑：好吧，map 将 iterable 作为参数（如列表、元组），但在这种情况下，传递的参数 score 是一个函数。而且您正在传递函数名称而不是调用该函数。因此，一个函数被传递给map() 函数。因此，您需要调用该函数。例如：

score_list = score(r.readline())
average = sum(list(map(int, score_list)))/len(score_list)

【讨论】：