【发布时间】:2021-08-09 21:02:27
【问题描述】:
我有一张包含双打列表的地图。
未排序的地图内容:{A=[0.02, 0.03], B=[0.0, 0.01], C=[0.01, 0.0], D=[0.05, 1.03], E=[1.01, 0.03]}
我需要对 List(0) 进行降序排序。我尝试了以下逻辑,但它按升序排序。
Map<String, List<Double>> map = new HashMap<>();
map.put("A", new ArrayList<Double>(Arrays.asList(0.02,0.03)));
map.put("B", new ArrayList<Double>(Arrays.asList(0.00,0.01)));
map.put("C", new ArrayList<Double>(Arrays.asList(0.01,0.00)));
map.put("D", new ArrayList<Double>(Arrays.asList(0.05,1.03)));
map.put("E", new ArrayList<Double>(Arrays.asList(1.01,0.03)));
Map<String, List<Double>> output = map.entrySet()
.stream()
.sorted(Comparator.comparing(o -> o.getValue().get(0)))
.collect(Collectors
.toMap(Map.Entry::getKey,Map.Entry::getValue,(a,b) ->a, LinkedHashMap :: new));
System.out.println("After sort: " + output);
实际输出: {B=[0.0, 0.01], C=[0.01, 0.0], A=[0.02, 0.03], D=[0.05, 1.03], E=[1.01, 0.03]}
预期输出: {E=[1.01, 0.03], D=[0.05, 1.03], A=[0.02, 0.03], C=[0.01, 0.0], B=[0.0, 0.1]}
请帮助我了解 Java8 流的逻辑。
【问题讨论】:
-
您拥有的
Comparator是Comparator<Map.Entry<String, List<Double>>> compareFirstValue = Comparator.comparing(o -> o.getValue().get(0));,但您需要的是Comparator<Map.Entry<String, List<Double>>> reversedOrder = compareFirstValue.reversed();..... 撇开:Arrays.asList(0.02,0.03)足以进行初始化。
标签: java sorting collections java-8