文本文件 - 多行字符串为一行

Question

我正在解析 txt 文件并执行一些编辑任务。我在将多行字符串更改为一行字符串时卡住了。

工作流程： 1）将多行合并为一行 2）提取包含一些字符或startsWith的特定行

已经尝试了一些方法，但没有想要的结果。

目标是拥有这一行：

Jrn.Directive "WindowSize"  , "[A.rvt]", "Floor Plan: Level 1" , 1912, 849

基于

 Jrn.Directive "WindowSize"  _
         , "[A.rvt]", "Floor Plan: Level 1" _
         , 1912, 849

试过了：

line.lines().collect(Collectors.joining("_"+"[\n]"));

或

line.replaceAll("  _\n" +
                        "         ,");

感谢您的任何建议 更新：

工作流程：

1. 文本包含以下文本（它是整个 txt 文件的一小部分） - 我无法将其粘贴为代码，请看截图

   Jrn.Directive "WindowSize" _ ，“[A.rvt]”，“平面图：1 级”_ , 1912, 849 ' 0:

请看截图https://i.ibb.co/0cRrwcR/2019-02-03-1947.png

1. 因为我将提取以 Jrn.D 开头的字符串等我需要 加入这个并获得

   Jrn.Directive "WindowSize" , "[A.rvt]", "平面图: Level 1" , 1912, 849

我认为有必要首先定义需要连接的行，然后我可以提取包含有趣信息的行，例如这些以 Jrn.D 开头的行。

编写我用来查找特定刺痛的代码

import java.io.*;
import java.util.stream.Collectors;
public class ReadFromFile {
    public static void main(String [] args) {
        // The name of the file to open.
        String fileName = "test.txt";

        // This will reference one line at a time
        String line = null;

        try {
            // FileReader reads text files in the default encoding.
            FileReader fileReader =
                    new FileReader(fileName);

            // Always wrap FileReader in BufferedReader.
            BufferedReader bufferedReader =
                    new BufferedReader(fileReader);

            while((line = bufferedReader.readLine()) != null) {

            // Im defining which lines are important for me but firstly I 
            //need have them in one line especially when looking for Jrn
                if (line.startsWith("Jrn")|| 
                line.contains("started recording journal file")|| 
                line.contains("' Build:")|| line.contains("Dim Jrn"))
                System.out.println(line);
            }
            // Always close files.
            bufferedReader.close();
        }
        catch(FileNotFoundException ex) {
            System.out.println(
                    "Unable to open file '" +
                            fileName + "'");
        }
        catch(IOException ex) {
            System.out.println(
                    "Error reading file '"
                            + fileName + "'");
            // Or we could just do this:
            // ex.printStackTrace();
        }

    }
}

Answer 1

我能想到的解决您的具体问题的最佳（对文件的干扰最小）方法是在Jrn.Directive 元信息的末尾添加一个分隔符（*），如果这在可能的范围内，例如：

Jrn.Directive "WindowSize" _ , "[A.rvt]", "Floor Plan: Level 1" _ , 1912, 849*

然后您可以使用循环连续打印每个与分隔符不匹配的标记，并在匹配时中断循环。

类似的东西

    //File object instantiation
    File file = new File("test.txt");

    //Iterator which loops over every line in the file
    Iterator<String> iterator = Files.readAllLines(file.toPath()).iterator();

    //The end delimiter for you Jrn.Directive information
    String delimiter = "*";

    while(iterator.hasNext()) {
            //String to store current line
            String line = iterator.next();
            //Execute if line starts with Jrn.Directive
            if (line.startsWith("Jrn")) {
                //JrnLoop to serialize Jrn.Directive information
                JrnLoop: while(true) {
                    //Splitting and processing each character in the current line
                    for(String token: line.split("")) {
                        //Escape and break the JrnLoop if the current character matches end delimiter
                        if (token.matches(delimiter)) {
                            System.out.println();
                            break JrnLoop;
                        }
                        //Otherwise print the current character
                        System.out.print(token);
                    }
                    //Go to the next line of the Jrn.Directive information
                    line = iterator.next();
                }
            }
            //If the line does not start with Jrn.Directive
            else {
                System.out.println(line);

        }

至于你的Jrn.Directive信息为什么会在文件中多行存储，我真的不知道