【发布时间】：2017-08-11 18:26:36
【问题描述】：
我创建了 2x1 矩阵系统，其中一个人捐款，捐款后他从两个人那里收到钱。我正在尝试创建一个人第一次（注册后）进入系统的情况，系统将检查系统中是否有任何人可以从该人那里接收资金，如果有的话人然后我正在检查该人是否已经收到两次付款如果该人收到两次付款该系统将检查系统中的下一个人并将再次执行该过程以检查该人是否已收到两次付款. 现在的问题是系统只检查 2 个人，例如系统是否正在找到一个人，并且该人已经恢复了两次付款系统将用于下一个，但如果下一个已收到，则系统应转到下一个，依此类推，除非他找到用户或没有用户。但是我的系统最多只能容纳两个人，我不知道我应该如何创建一个循环，以便系统检查数据库中的整个用户。
public function allotDonar($id) {
$date = date('Y-m-d h:i:s a');
$currentDate = strtotime($date);
$futureDate = $currentDate+(60*1);
$formatDate = date("Y-m-d h:i:s a", $futureDate);
$endDate = date("Y-m-d h:i:s a", strtotime('+30 hours'));
$get = $this -> db -> query("Select user.id, user.super, user.name,
user.canRecieve, user.active, user.blocked, user_packages.packageID, user.type,
user_packages.userID from (Select user.id AS USERID, canRecieve, type, super,
status, packageID, active from user JOIN user_packages ON user.id='$id' AND
user.type='0' AND user.super='0' AND user.canRecieve='0' AND user.active='1' AND
user_packages.userID=user.id AND user_packages.status='1') AS DONOR JOIN user ON
user.id!='$id' AND user.canRecieve='1' AND user.active='1' AND user.blocked='0'
AND user.type='0' AND user.super='0' JOIN user_packages ON
user.id=user_packages.userID AND user_packages.status='1' AND
user_packages.packageID=DONOR.packageID ORDER BY user.id ASC");
if($get -> num_rows() > 0) {
$UserInfo = $get -> row();
$key = $get -> result();
$sql = "Select * from donar where packageID=? AND reciever_id=?";
$query = $this -> db -> query($sql, array($UserInfo -> packageID, $UserInfo -> id));
// return $query -> result();
if($query -> num_rows() >= 2) {
// return 'Persons';
// if user cycle has not been completed but user has tow recievings in the table then again search fot the next user in the array
$nexPerson = current(array_slice($key, array_search($key, array_keys($key)) + 1, 1));
if(!empty($nexPerson)) {
$nextPersonID = $nexPerson -> id;
// check if next pserons has paid money or not
$checkIfNextPaid = $this -> db -> query("Select * from user where canRecieve='1'");
if($checkIfNextPaid -> num_rows() > 0) {
$sql = "Select * from donar where packageID=? AND reciever_id=?";
$query = $this -> db -> query($sql, array($nexPerson -> packageID, $nexPerson -> id));
// return $query -> result();
if($query -> num_rows() >= 2) {
//$this -> allotDonar($id);
}
else {
$sql = "Select * from donar where packageID=? AND donarID=?";
$query = $this -> db -> query($sql, array($UserInfo -> packageID, $id));
if($query -> num_rows() >= 1) {
}
else {
// $currentID = $UserInfo -> id;
$allotDonar = $this -> db -> insert('donar', array('donarID' => $id, 'reciever_id' => $nexPerson -> id, 'packageID' => $nexPerson -> packageID, 'date_added' => $date, 'date_expiry' => $endDate, 'wait_time' => $formatDate, 'wait_start' => $date));
return $this -> db -> insert_id();
}
}
}
}
}
else {
$sql = "Select * from donar where packageID=? AND donarID=?";
$query = $this -> db -> query($sql, array($UserInfo -> packageID, $id));
if($query -> num_rows() >= 1) {
}
else {
// if the rows of the user are less then 2 record then simply insert the erecord of the user
$allotDonar = $this -> db -> insert('donar', array('donarID' => $id, 'reciever_id' => $UserInfo -> id, 'packageID' => $UserInfo -> packageID, 'date_added' => $date, 'date_expiry' => $endDate, 'wait_time' => $formatDate, 'wait_start' => $date));
return $this -> db -> insert_id();
}
}
}
else {
return 'No person found';
}
请帮我让这个系统检查数据库中的所有用户。
【问题讨论】：