我可以使用 for-loop 来获得相同的结果吗？ [关闭]

Question

这段代码运行良好，但我想知道是否可以使用 for-loop 获得相同的功能？

    storm_halted=False
    while True:
        input=raw_input(">  ")
        if "stay" in input:
            print dead("You were struck by lightning !")
        elif "wait" in input and not storm:
            print "The storm has stpped !"
            storm_halted=True
        elif "wait" in input and storm:
            print dead("You are lazy")
        elif "room" in input and storm :
            gold ()
        else:
            print dead("Type something")

Answer 1

对于此代码，您不能将输入用作变量，因此我将其重写为：

   choice = input("") #This will get a string that the user types.        

   if "stay" in choice: #This will execute the code below if the user has typed something with stay in it
        print dead("You were struck by lightning !")

    elif "wait" in choice and not(storm): #this will execute the code below if the user has typed something with the word wait in it and there is no storm(storm=False)
        print "The storm has stpped !"
        storm_halted=True

    elif "wait" in input and storm: #this will execute the code below if the user has typed something with the word wait in it and there is a storm (storm=True)
        print dead("You are lazy")
    elif "room" in input and storm : #this will execute the code below if the user has typed something with the word room in it and there is a storm (storm=True)
        gold ()
    else: #This code will execute if none of the above happen
        print dead("Type something")

as for thestorm_halted = True 对应的英文是：暴风雨已经停止。尽管我认为您不小心将 elif 中的 not(storm) 和storm 颠倒过来了——从等价物的意义上来看。

希望这可以帮助您理解。真的没有太多其他方法可以实现这一点，而且绝对没有更简单的方法。