【问题标题】:How to connect android to a remote database [closed]如何将android连接到远程数据库[关闭]
【发布时间】:2012-07-12 02:23:10
【问题描述】:

我正在开发一个必须将数据存储在数据库中的 Android 应用。 该数据库还必须由 iPhone 应用程序和 Web 应用程序访问。 我想为此使用 Mysql,因为它是开源的。

我正在寻找这方面的一些信息,显然我需要创建一个网络服务 连接到数据库。可能在php中,但我对php没有任何经验...

如何编写此 Web 服务以及将其存储在哪里?我在哪里创建和存储数据库? ...

谁能帮我解决这个问题?

tnx

【问题讨论】:

标签: java php android mysql web-services


【解决方案1】:

使用 SQL Server 管理桌面上的数据并在 Visual Studio 上的 .Net 中创建 Web 服务。

然后连接到应用程序中的网络服务并从数据库中设置/获取数据。

关于如何在 .NET 中创建 Web 服务的链接(不包括在 Android 中的实现):http://srikanthtechnologies.com/blog/dotnet/wsdaljava.aspx

有关如何将您的服务与 Android 连接的链接:http://seesharpgears.blogspot.in/2010/11/basic-ksoap-android-tutorial.html

http://www.codeproject.com/Articles/304302/Calling-Asp-Net-Webservice-ASMX-From-an-Android-Ap

http://adrianandroid.blogspot.in/2012/05/access-c-net-web-service-in.html

【讨论】:

  • 点击这些链接并开始编码。如果您遇到任何问题,请发布您的问题。干杯。 :)
  • +1 对于 web 服务 客户端数据交换协议,我建议使用 JSON
  • 其他数据库和技术可用...
  • @DaveRlz :是的,我知道还有很多其他方法可以做到这一点。我只是建议一个(我觉得最简单的)。你的观点可能明显不同。 :)
【解决方案2】:

我的自定义类将联系本地主机服务器(WAMP 或 XAMP 服务器)

CustomHttpClient.java

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.net.URI;
import java.util.ArrayList;
import org.apache.http.HttpResponse;
import org.apache.http.NameValuePair;
import org.apache.http.client.HttpClient;
import org.apache.http.client.entity.UrlEncodedFormEntity;
import org.apache.http.client.methods.HttpGet;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.conn.params.ConnManagerParams;
import org.apache.http.impl.client.DefaultHttpClient;
import org.apache.http.params.HttpConnectionParams;
import org.apache.http.params.HttpParams;

public class CustomHttpClient {
    /** The time it takes for our client to timeout */
    public static final int HTTP_TIMEOUT = 30 * 1000; // milliseconds

    /** Single instance of our HttpClient */
    private static HttpClient mHttpClient;

    /*
     * Get our single instance of our HttpClient object.
     * 
     * @return an HttpClient object with connection parameters set
     */
    private static HttpClient getHttpClient() {
        if (mHttpClient == null) {
            mHttpClient = new DefaultHttpClient();
            final HttpParams params = mHttpClient.getParams();
            HttpConnectionParams.setConnectionTimeout(params, HTTP_TIMEOUT);
            HttpConnectionParams.setSoTimeout(params, HTTP_TIMEOUT);
            ConnManagerParams.setTimeout(params, HTTP_TIMEOUT);

        }
        return mHttpClient;
    }

    /*
     * Performs an HTTP Post request to the specified url with the specified
     * parameters.
     * 
     * @param url The web address to post the request to
     * 
     * @param postParameters The parameters to send via the request
     * 
     * @return The result of the request
     * 
     * @throws Exception
     */ 
    public static String executeHttpPost(String url,
    ArrayList<NameValuePair> postParameters) throws Exception {

        BufferedReader in = null;
        try 
        { 
            HttpClient client = getHttpClient();
            HttpPost request = new HttpPost("http://192.168.1.38/" +url (pathoffilenameyouarecalling));
            UrlEncodedFormEntity formEntity = new UrlEncodedFormEntity(postParameters);
            request.setEntity(formEntity);
            HttpResponse response = client.execute(request);
            in = new BufferedReader(new InputStreamReader(response.getEntity().getContent()));

            StringBuffer sb = new StringBuffer("");
            String line = "";
            String NL = System.getProperty("line.separator");
            while ((line = in.readLine()) != null) 
            {
                sb.append(line + NL);
            }

            in.close();

            String result = sb.toString();
            return result;
        } finally {
            if (in != null) {
                try {
                    in.close();
                } catch (IOException e) {
                    e.printStackTrace();
                }
            }
        }
    }

    /**
     * Performs an HTTP GET request to the specified url.
     * 
     * @param url
     *            The web address to post the request to
     * @return The result of the request
     * @throws Exception
     */
    public static String executeHttpGet(String url) throws Exception {
        BufferedReader in = null;
        try {
            HttpClient client = getHttpClient();
            HttpGet request = new HttpGet();
            request.setURI(new URI(url));
            HttpResponse response = client.execute(request);
            in = new BufferedReader(new InputStreamReader(response.getEntity()
                    .getContent()));

            StringBuffer sb = new StringBuffer("");
            String line = "";
            String NL = System.getProperty("line.separator");
            while ((line = in.readLine()) != null) {
                sb.append(line + NL);
            }
            in.close();

            String result = sb.toString();
            return result;
        } finally {
            if (in != null) {
                try {
                    in.close();
                } catch (IOException e) {
                    e.printStackTrace();
                }
            }
        }
    }
}

调用它的类会这样实现。

ArrayList<NameValuePair> postParameter = new ArrayList<NameValuePair>();
postParameter.add(new BasicNameValuePair("parametertobesent",value));
respons = CustomHttpClient.executeHttpPost("urlofservice",postParameter);

php 文件应该存在于 XAMP 服务器的 htdocs 中

【讨论】:

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