通过 HttpResponse Java 下载 Zip 文件

Question

因此，我从数据库（各种 mimetypes）中获取 blob 集合，并尝试将它们压缩以供用户通过 http 响应下载。我可以进行下载，但是当我尝试打开下载的 zip 文件时，它显示“存档格式未知或已损坏”。我已经使用 application/zip、application/octet-stream 和 application/x-zip-compressed 尝试了以下代码，但我开始认为问题在于我如何添加文件。我也在使用 Java 7 和 Grails 2.2.4。

对此的任何帮助将不胜感激。谢谢！

  final ZipOutputStream out = new ZipOutputStream(new FileOutputStream("test.zip"));


        for (Long id : ids){

            Object[] stream = inlineSamplesDataProvider.getAttachmentStream(id);


            if (stream) {

                String fileName = stream[0]
                String mimeType = (String) stream[1];
                InputStream inputStream = stream[2]
                byte[] byteStream = inputStream.getBytes();

                ZipEntry zipEntry = new ZipEntry(fileName)
                out.putNextEntry(zipEntry);
                out.write(byteStream, 0, byteStream.length);
                out.closeEntry();
            }
        }

        out.close();
        response.setHeader("Content-Disposition", "attachment; filename=\"" + "test.zip" + "\"");
        response.setHeader("Content-Type", "application/zip");
        response.outputStream << out;
        response.outputstream.flush();

Answer 1

我在这里找到了答案：Returning ZipOutputStream to browser

好吧，最终对我有用的是将 ZipOutputStream 转换为 ByteArrayOutputStream 并将其作为 byte[] 写入响应：

ByteArrayOutputStream baos = new ByteArrayOutputStream();
final ZipOutputStream out = new ZipOutputStream(baos);

Calendar cal = Calendar.getInstance();
String date = new SimpleDateFormat("MMM-dd").format(cal.getTime());

final String zipName = "COA_Images-" + date + ".zip";

for (Long id: ids) {

    Object[] stream = inlineSamplesDataProvider.getAttachmentStream(id);

    if (stream) {

        String fileName = stream[0];
        String mimeType = (String) stream[1];
        InputStream inputStream = stream[2];
        byte[] byteStream = inputStream.getBytes();

        ZipEntry zipEntry = new ZipEntry(fileName)
        out.putNextEntry(zipEntry);
        out.write(byteStream, 0, byteStream.length);
        out.closeEntry();
    }
}

out.close();

response.setHeader("Content-Disposition", "attachment; filename=\"" + zipName + "\"");
response.setHeader("Content-Type", "application/zip");
response.getOutputStream().write(baos.toByteArray());
response.flushBuffer();
baos.close();

感谢所有帮助过的人！