【发布时间】:2014-10-31 05:23:36
【问题描述】:
我正在使用 Spring Boot 并希望使用 Controller 来接收分段文件上传。 发送文件时,我不断收到 error 415 unsupported content type 响应,并且永远无法到达控制器
There was an unexpected error (type=Unsupported Media Type, status=415).
Content type 'multipart/form-data;boundary=----WebKitFormBoundary1KvzQ1rt2V1BBbb8' not supported
我尝试在 html/jsp 页面中以及在使用 RestTemplate 的独立客户端应用程序中使用 form:action 发送。所有尝试都给出相同的结果
multipart/form-data;boundary=XXXXX not supported.
从多部分文档看来,边界参数必须添加到多部分上传中,但这似乎与接收 "multipart/form-data" 的控制器不匹配
我的控制器方法设置如下
@RequestMapping(value = "/things", method = RequestMethod.POST, consumes = "multipart/form-data" ,
produces = { "application/json", "application/xml" })
public ResponseEntity<ThingRepresentation> submitThing(HttpServletRequest request,
@PathVariable("domain") String domainParam,
@RequestParam(value = "type") String thingTypeParam,
@RequestBody MultipartFile[] submissions) throws Exception
使用 Bean 设置
@Bean
public MultipartConfigElement multipartConfigElement() {
return new MultipartConfigElement("");
}
@Bean
public MultipartResolver multipartResolver() {
org.springframework.web.multipart.commons.CommonsMultipartResolver multipartResolver = new org.springframework.web.multipart.commons.CommonsMultipartResolver();
multipartResolver.setMaxUploadSize(1000000);
return multipartResolver;
}
如您所见,我已将消费类型设置为“multipart/form-data”,但是当发送多部分时,它必须有一个边界参数并放置一个随机边界字符串。
谁能告诉我如何设置控制器中的内容类型以匹配或更改我的请求以匹配我的控制器设置?
我尝试发送... 尝试 1...
<html lang="en">
<body>
<br>
<h2>Upload New File to this Bucket</h2>
<form action="http://localhost:8280/appname/domains/abc/things?type=abcdef00-1111-4b38-8026-315b13dc8706" method="post" enctype="multipart/form-data">
<table width="60%" border="1" cellspacing="0">
<tr>
<td width="35%"><strong>File to upload</strong></td>
<td width="65%"><input type="file" name="file" /></td>
</tr>
<tr>
<td> </td>
<td><input type="submit" name="submit" value="Add" /></td>
</tr>
</table>
</form>
</body>
</html>
尝试 2....
RestTemplate template = new RestTemplate();
MultiValueMap<String, Object> parts = new LinkedMultiValueMap<String, Object>();
parts.add("file", new FileSystemResource(pathToFile));
try{
URI response = template.postForLocation(url, parts);
}catch(HttpClientErrorException e){
System.out.println(e.getResponseBodyAsString());
}
尝试 3...
FormHttpMessageConverter formHttpMessageConverter = new FormHttpMessageConverter();
formHttpMessageConverter.setCharset(Charset.forName("UTF8"));
RestTemplate restTemplate = new RestTemplate();
restTemplate.getMessageConverters().add( formHttpMessageConverter );
restTemplate.getMessageConverters().add(new MappingJackson2HttpMessageConverter());
restTemplate.setRequestFactory(new HttpComponentsClientHttpRequestFactory());
MultiValueMap<String, Object> map = new LinkedMultiValueMap<String, Object>();
map.add("file", new FileSystemResource(path));
HttpHeaders imageHeaders = new HttpHeaders();
imageHeaders.setContentType(MediaType.MULTIPART_FORM_DATA);
HttpEntity<MultiValueMap<String, Object>> imageEntity = new HttpEntity<MultiValueMap<String, Object>>(map, imageHeaders);
ResponseEntity e= restTemplate.exchange(uri, HttpMethod.POST, imageEntity, Boolean.class);
System.out.println(e.toString());
【问题讨论】:
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你的域名是怎么写的?
标签: java spring spring-mvc spring-boot multipart