【问题标题】:django.urls.exceptions.NoReverseMatch: Reverse for 'Professors' with arguments '(1, 5)' not founddjango.urls.exceptions.NoReverseMatch:找不到带有参数“(1、5)”的“教授”的反向
【发布时间】:2019-07-10 17:00:49
【问题描述】:

我正在尝试过滤我的教授表以显示与特定学校和特定专业对应的教授,参数显示在错误消息中,我只是不明白为什么会出现错误消息.

Views.py

from django.http import HttpResponse
from django.shortcuts import render
from .models import professor, School, Major, School_Major

def index(request):
    schools = School.objects.all()
    return render(request, 'locate/index.html', {'schools': schools})


# def Major(request, Major):
#   major_choice = professor.objects.filter(Major =Major)
#   return render(request, 'locate/major.html', {'major_choice': major_choice})

def Majors(request, school_pk):
    schools_majors_ids = []
    major_after_filter = []

    #Filter to a show the association of 1 schools majors
    school_choice = School_Major.objects.filter(school_id = school_pk)

    #Append each of the major id's to school_majors_ids list
    for store in school_choice:
        schools_majors_ids.append(store.major_id)

    #Filter majors names required
    for store in schools_majors_ids:
        name = Major.objects.get(id = store)
        major_after_filter.append(name)
    return render(request, 'locate/major.html', {'major_after_filter' : major_after_filter,
                                                 'school_pk' : school_pk})

def Professors(request, school_pk, major_pk):
    professors = professors.objects.filter(school_id = school_pk).filter(major_id = major_pk)
    return render(request, 'locate/professors', {'professors' : professors})

url.py

from django.urls import path

from . import views


urlpatterns = [
    path('', views.index, name='index'),
    path(' <int:school_pk>/', views.Majors, name='Major'),
    path(' <int:school_pk/<int:major_pk>/', views.Professors, name="Professors")
]

majors.html

<h3 id="test">{{school_pk}}</h3>
            <ul>
                {% for major in major_after_filter %}

                <li><a href="{% url 'Professors' school_pk major.id %}">{{major.name}}</a></li>

                {%endfor%}
            </ul>

我需要一种方法来放置学校主键的值以及专业主键作为教授视图函数的参数,以便能够过滤教授表以显示正确的专业。

当我离开 school_pk 时,如下所示

我收到以下错误

django.urls.exceptions.NoReverseMatch: Reverse for 'Professors' with arguments '(1, 5)' not found. 1 pattern(s) tried: ['locate/\\ <int:school_pk/(?P<major_pk>[0-9]+)/$']

当我像下面这样删除 school_pk 时

<li><a href="{% url 'Professors' major.id %}">{{major.name}}</a></li>

我收到此错误

TypeError: Professors() missing 1 required positional argument: 'school_pk'

这是有道理的,因为教授函数需要一个 school_pk 参数(请注意,html 中使用的变量和参数名称相同,如果这看起来令人困惑,请见谅)。

【问题讨论】:

    标签: django python-3.x django-templates django-views


    【解决方案1】:

    您的网址格式中缺少右括号。

    path('<int:school_pk>/<int:major_pk>/', 
                        ^
    

    【讨论】:

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