'initial' 是此函数的无效关键字参数

Question

我收到此错误“'initial' is an invalid keyword argument for this function”，我正在尝试通过 createview 创建一个对象，这是什么错误，为什么会出现此错误？

urls.py

from django.conf.urls import url
from . import views

urlpatterns = [
url(r'^add/$', views.CriarTrabalhador.as_view(), name='add')]

---

models.py

from django.db import models

    # Create your models here.

    class Trabalhadores(models.Model):
        Nome = models.CharField('Name',max_length=100)
        Cpf = models.CharField(primary_key=True,max_length=11)
        Data = models.DateField('Data de Nascimento')

        def __str__(self):
            return self.Nome

---

forms.py

   from django import forms
   from .models import Trabalhadores

    class TrabalhadoresForm(forms.ModelForm):
        class Meta:
           model = Trabalhadores
                fields = ["Nome","Cpf","Data"]

---

views.py

from django.shortcuts import render
from django.views.generic.list import ListView
from django.core.urlresolvers import reverse
from .models import Trabalhadores
from django.views.generic.detail import DetailView
from django.views.generic.edit import UpdateView,CreateView
from . import forms

class CriarTrabalhador(CreateView):
    model = Trabalhadores
    form_class = forms.Trabalhadores
    template_name = 'mytemp/adicionartrabalhador.html'

    def get_success_url(self):
        return reverse('trabalhadores')

编辑

提交表单后，我得到了这个网址

localhost/add/?csrfmiddlewaretoken=PVjqYnZNwJZpHuObu1OXNSnIekeqMVVeNIIxTkr2UFH7ii83QScfGdBrX5HjmZCe&Nome=test&Cpf=00000000000&Data=1998-12-14

为什么会这样？

Answer 1

你必须把你的 form_class 等于你的表单

像 form_class=TrabalhadoresForm 一样，因为您正在使用 from 类创建视图，并且数据将通过您的模型类传递 所有类型的 Django 通用类视图都相同

Answer 2

您已将该视图中的 form_class 设置为 Trabalhadores，即模型，而不是 TrabalhadoresForm，即表单。