使用 Python 将文件上传到 Sharepoint 文件夹

Question

我有一个 Python 脚本，可以将文件保存到服务器共享文件夹以供用户访问。我们的组织最近将我们的服务器文件结构移动到了 Sharepoint... 包括所有文件夹。 （我已经阅读了多篇文章，这是一个坏主意，但现在没有改变它。）

我有将文件上传到 Sharepoint 库的根文件夹的新代码：

导入共享 s = sharepy.connect("site.sharepoint.com", "username", "password") r = s.post("https://site.sharepoint.com/_api/web/Lists/GetByTitle('Documents')/RootFolder/files\ /add(覆盖=true,url='test.csv')", \ “测试，富，酒吧”） 打印(r)

有没有办法将文件上传到子文件夹而不是根目录？如果有，怎么做？

Answer 1

是的，您可以通过 rest api 将文件上传到子文件夹。请参考以下端点：

• Add method to create a file
• create a file and add it to a folder

下面是一些关于如何使用 python 上传文件的演示（但它们可能不会使用与您相同的库）。

• SharePlum
• Office365-REST-Python-Client

/////// 更新 //////

Answer 2

如果它对任何人有帮助，这是我的最终代码。它成功地将文件发布到共享点站点团队站点库子文件夹。用您的信息替换斜体。

import sharepy 

s = sharepy.connect("*MySite*.sharepoint.com", "*username*", "*password*") 

r = s.post("https://*MySite*.sharepoint.com/sites/*TeamSiteName*/_api/web/GetFolderByServerRelativeUrl('/sites/*TeamSiteName*/Shared Documents/*FolderName*')/Files/" + "add(overwrite=true,url='test.csv')", "testing,foo,bar")

print r

Answer 3

前段时间我曾解决过同样的问题。下面是我的代码。

import requests
from shareplum import Office365

username = "YourUsername"
password = "YourPassword"
site_name = "Sitename"
doc_library = "SubfolderName"
base_path = "https://domainName.sharepoint.com"

file_name = "FileName"

# Obtain auth cookie
authcookie = Office365(base_path, username=username, password=password).GetCookies()
session = requests.Session()
session.cookies = authcookie
session.headers.update({'user-agent': 'python_bite/v1'})
session.headers.update({'accept': 'application/json;odata=verbose'})

# dirty workaround.... I'm getting the X-RequestDigest from the first failed call
session.headers.update({'X-RequestDigest': 'FormDigestValue'})
response = session.post( url=base_path + "/sites/" + site_name + "/_api/web/GetFolderByServerRelativeUrl('" + doc_library + "')/Files/add(url='a.txt',overwrite=true)",
                         data="")
session.headers.update({'X-RequestDigest': response.headers['X-RequestDigest']})

dest =  base_path + "/sites/" + site_name + "/_api/web/GetFolderByServerRelativeUrl('" + doc_library + "')/Files/add(url='a.txt',overwrite=true)" #session.post( url=base_path + "/sites/" + site_name + "/_api/web/GetFolderByServerRelativeUrl('" + doc_library + "')/Files/add(url='a.txt',overwrite=true)",data="")
print('Folder!')
# perform the actual upload
with open( file_name, 'rb') as file_input:
    try:
        print('uploading')
        response = session.post( 
            url=base_path + "/sites/" + site_name + "/_api/web/GetFolderByServerRelativeUrl('" + doc_library + "')/Files/add(url='" 
            + file_name + "',overwrite=true)",
            data=file_input)
    except Exception as err: 
        print("Some error occurred: " + str(err))
print('Uploaded successfully!')

Answer 4

经过这么多尝试，我终于用比我预期的更少的行编码完成了这项工作。

我在某些 url 和文件夹路径方面遇到了一些问题，这就是为什么我将“r”放在获取原始路径的原因。

来自 shareplum 导入站点 从 shareplum 导入 Office365 从 shareplum.site 导入版本

普通认证

authcookie = Office365(r'https://.sharepoint.com', username='@', password='***').GetCookies()

在这里填写您网站上的信息

site = Site(r'https://*******.sharepoint.com/sites/sitename/',version=Version.v365, authcookie=authcookie)

在这里你只需填写文件夹的信息

folder = site.Folder('共享文档/您的文件夹')

来源：https://shareplum.readthedocs.io/en/latest/files.html#folders

编码和错误是可选的

使用 open(r'C:/Users/Alessandro.paiva/Desktop/file.xlsx', encoding = 'latin-1', errors = 'ignore') 作为文件： fileContent = file.read()

文件名

folder.upload_file(fileContent, r'file.xlsx')

Answer 5

以下是我使用 Databricks 中的 python 将文件从 Azure Blob 存储上传到 Sharepoint 上的新子文件夹的代码。

def upload_sharepoint(sp_filepath,blob_file_path):
  from office365.runtime.auth.authentication_context import AuthenticationContext
  from office365.sharepoint.client_context import ClientContext
  from office365.sharepoint.files.file import File
  import os
  
  url='https://<domain>.sharepoint.com/sites/<site1>/<subsite1>'
  username = 'user'
  pwd = 'password'

  ctx_auth = AuthenticationContext(url)
  ctx_auth.acquire_token_for_user(username, pwd)   
  ctx = ClientContext(url, ctx_auth)

  blobpath = '/dbfs' + blob_file_path
  filename=os.path.basename(blob_file_path)
  
  #read content of file
  with open(blobpath, 'rb') as content_file:
    file_content = content_file.read()
  
  target_url = sp_filepath  # sharepoint url to upload a file 
  target_folder=ctx.web.get_folder_by_server_relative_url(target_url)
  try:
    folder_exist=ctx.load(target_folder).execute_query().properties['Exists']
  except Exception as e:
    folder_exist=False
    print('Folder Not Found,Creating Folder')
    
  if !folder_exist:
    try:
      target_folder = ctx.web.folders.add(target_url).execute_query()    #Create the folder, can create folder upto 1 level only
    except Exception as e:
      print('Parent folder Not Found',e)
  target_folder.upload_file(filename, file_content).execute_query()    # upload the file
  print('Uploaded '+filename+' to '+target_url)

以上代码可用于在已存在的文件夹中创建一级子文件夹。

例如，在这里我们将在 Sharepoint 上存在的“支付文件”文件夹中创建一个文件夹名称“NewFolder”：

sharepoint_fp='/sites/<site1>/<subsite1>/Document%20upload/Pay%20file/NewFolder' 
blob_path='/mnt/PayFile/'  
files=spark.createDataFrame(dbutils.fs.ls(blob_path))
files=files.select('name').collect()
for f in files:
  upload_sharepoint(sharepoint_fp,blob_path+f.name)