按前 10 个字符拆分列表中的字符串，Python

Question

我正在尝试获取亚马逊上每个产品的 ASIN 号，它是 dp/ 之后的前十位数字。我已经到了我有数字但后面仍然有垃圾的地步。有什么帮助吗？

   product_lst = [
            "https://www.amazon.com/Bentgo-Kids-Prints-Camouflage-5-Compartment/dp/B07R2CNSTK/ref=zg_bs_toys-and-games_home_2?_encoding=UTF8&psc=1&refRID=S3ESVW604M2GF8VYYVAZ",
            "https://www.amazon.com/Hamdol-Inflatable-Swimming-Sprinkler-Full-Sized/dp/B08SLYY1WD/?_encoding=UTF8&smid=AYKJMONAWDIKA&pf_rd_p=287d7433-71c6-4904-99b3-55833d0daaa0&pd_rd_wg=lMKJu&pf_rd_r=CR8F460JV643467SAG8Q&pd_rd_w=KgWnp&pd_rd_r=0e298b4a-6e52-4688-87bb-482fb6c1a56b&ref_=pd_gw_deals",
            "https://www.amazon.com/Fire-TV-Stick-4K-with-Alexa-Voice-Remote/dp/B079QHML21?ref=deals_primeday_deals-grid_slot-5_21f9_dt_dcell_img_0_ca4a9dae",
            "https://www.amazon.com/dp/B089RDSML3",
            "https://www.amazon.com/Lucky-Brand-Burnout-Notch-Shirt/dp/B081J8SGH7/ref=sr_1_2?dchild=1&pf_rd_i=7147441011&pf_rd_m=ATVPDKIKX0DER&pf_rd_p=e6aa97f3-9bc4-42c5-ac38-37844f71b469&pf_rd_r=S2F3A95JN2FDGBQ4V048&pf_rd_s=merchandised-search-9&pf_rd_t=101&qid=1624427428&s=apparel&sr=1-2"
        ]
for url in product_lst:
    product_lst = url.split("dp/")
    for url in product_lst:
        del product_lst[::2]
    print(product_lst)

输出：

['B07R2CNSTK/ref=zg_bs_toys-and-games_home_2?_encoding=UTF8&psc=1&refRID=S3ESVW604M2GF8VYYVAZ'] [ 'B08SLYY1WD / 编码= UTF8＆SMID = AYKJMONAWDIKA＆pf_rd_p = 287d7433-71c6-4904-99b3-55833d0daaa0＆pd_rd_wg = lMKJu＆pf_rd_r = CR8F460JV643467SAG8Q＆pd_rd_w = KgWnp＆pd_rd_r = 0e298b4a-6e52-4688-87bb-482fb6c1a56b＆REF EM> = pd_gw_deals']，点击 ['B079QHML21?ref=deals_primeday_deals-grid_slot-5_21f9_dt_dcell_img_0_ca4a9dae'] ['B089RDSML3'] [ 'B081J8SGH7 / REF = sr_1_2？dchild = 1＆pf_rd_i = 7147441011＆pf_rd_m = ATVPDKIKX0DER＆pf_rd_p = e6aa97f3-9bc4-42c5-ac38-37844f71b469＆pf_rd_r = S2F3A95JN2FDGBQ4V048＆pf_rd_s =商品化搜索-9＆pf_rd_t = 101＆QID = 1624427428＆S =服饰＆SR = 1-2'] P>

Answer 1

对于文本搜索，module re (regex) 是一个不错的选择：

product_lst = [
"https://www.amazon.com/Bentgo-Kids-Prints-Camouflage-5-Compartment/dp/B07R2CNSTK/ref=zg_bs_toys-and-games_home_2?_encoding=UTF8&psc=1&refRID=S3ESVW604M2GF8VYYVAZ",
"https://www.amazon.com/Hamdol-Inflatable-Swimming-Sprinkler-Full-Sized/dp/B08SLYY1WD/?_encoding=UTF8&smid=AYKJMONAWDIKA&pf_rd_p=287d7433-71c6-4904-99b3-55833d0daaa0&pd_rd_wg=lMKJu&pf_rd_r=CR8F460JV643467SAG8Q&pd_rd_w=KgWnp&pd_rd_r=0e298b4a-6e52-4688-87bb-482fb6c1a56b&ref_=pd_gw_deals",
"https://www.amazon.com/Fire-TV-Stick-4K-with-Alexa-Voice-Remote/dp/B079QHML21?ref=deals_primeday_deals-grid_slot-5_21f9_dt_dcell_img_0_ca4a9dae",
"https://www.amazon.com/dp/B089RDSML3",
"https://www.amazon.com/Lucky-Brand-Burnout-Notch-Shirt/dp/B081J8SGH7/ref=sr_1_2?dchild=1&pf_rd_i=7147441011&pf_rd_m=ATVPDKIKX0DER&pf_rd_p=e6aa97f3-9bc4-42c5-ac38-37844f71b469&pf_rd_r=S2F3A95JN2FDGBQ4V048&pf_rd_s=merchandised-search-9&pf_rd_t=101&qid=1624427428&s=apparel&sr=1-2"
]

import re

results = []
for url in product_lst:
    m = re.search(r"/dp/([^/?]+)",url)
    if m:
        results.append(m.groups()[0])
print(results)

输出：

['B07R2CNSTK', 'B08SLYY1WD', 'B079QHML21', 'B089RDSML3', 'B081J8SGH7']

我使用r"/dp/([^/?]+)" 作为模式，归结为/dp/ 之后的任何内容的分组匹配，然后匹配下一个/ 或? 之前的所有内容。

你可以在线测试正则表达式——我使用http://regex101.com（用于复杂的）——它甚至可以根据你在其字段中插入的内容提供python代码（虽然不使用它；o））

---

您可以将自己的代码更改为

for url in product_lst:
    part = url.split("dp/")
    if len(part) > 1:            # blablubb dp/ more things => 2 or more parts
        print(part[1])           # print whats is left after dp/

为了避免覆盖您的列表product_lst - 但是您仍然需要在 / 和 ?用它。

Answer 2

在split() 上'dp/' 之后，绝对没有理由循环。您确切地知道您想要的数据在哪里，所以直接获取它：

   product_lst = [
            "https://www.amazon.com/Bentgo-Kids-Prints-Camouflage-5-Compartment/dp/B07R2CNSTK/ref=zg_bs_toys-and-games_home_2?_encoding=UTF8&psc=1&refRID=S3ESVW604M2GF8VYYVAZ",
            "https://www.amazon.com/Hamdol-Inflatable-Swimming-Sprinkler-Full-Sized/dp/B08SLYY1WD/?_encoding=UTF8&smid=AYKJMONAWDIKA&pf_rd_p=287d7433-71c6-4904-99b3-55833d0daaa0&pd_rd_wg=lMKJu&pf_rd_r=CR8F460JV643467SAG8Q&pd_rd_w=KgWnp&pd_rd_r=0e298b4a-6e52-4688-87bb-482fb6c1a56b&ref_=pd_gw_deals",
            "https://www.amazon.com/Fire-TV-Stick-4K-with-Alexa-Voice-Remote/dp/B079QHML21?ref=deals_primeday_deals-grid_slot-5_21f9_dt_dcell_img_0_ca4a9dae",
            "https://www.amazon.com/dp/B089RDSML3",
            "https://www.amazon.com/Lucky-Brand-Burnout-Notch-Shirt/dp/B081J8SGH7/ref=sr_1_2?dchild=1&pf_rd_i=7147441011&pf_rd_m=ATVPDKIKX0DER&pf_rd_p=e6aa97f3-9bc4-42c5-ac38-37844f71b469&pf_rd_r=S2F3A95JN2FDGBQ4V048&pf_rd_s=merchandised-search-9&pf_rd_t=101&qid=1624427428&s=apparel&sr=1-2"
        ]
for url in product_lst:
    split_lst = url.split("dp/")
    print(split_lst[1][:10]

我假设 ASIN 始终为 10 个字符。如果有更多字符，请调整拼接并且它始终是固定的。否则，您将需要找到不同的方法。

Answer 3

无需拆分数据，直接获取ASIN。

product_lst = [
            "https://www.amazon.com/Bentgo-Kids-Prints-Camouflage-5-Compartment/dp/B07R2CNSTK/ref=zg_bs_toys-and-games_home_2?_encoding=UTF8&psc=1&refRID=S3ESVW604M2GF8VYYVAZ",
            "https://www.amazon.com/Hamdol-Inflatable-Swimming-Sprinkler-Full-Sized/dp/B08SLYY1WD/?_encoding=UTF8&smid=AYKJMONAWDIKA&pf_rd_p=287d7433-71c6-4904-99b3-55833d0daaa0&pd_rd_wg=lMKJu&pf_rd_r=CR8F460JV643467SAG8Q&pd_rd_w=KgWnp&pd_rd_r=0e298b4a-6e52-4688-87bb-482fb6c1a56b&ref_=pd_gw_deals",
            "https://www.amazon.com/Fire-TV-Stick-4K-with-Alexa-Voice-Remote/dp/B079QHML21?ref=deals_primeday_deals-grid_slot-5_21f9_dt_dcell_img_0_ca4a9dae",
            "https://www.amazon.com/dp/B089RDSML3",
            "https://www.amazon.com/Lucky-Brand-Burnout-Notch-Shirt/dp/B081J8SGH7/ref=sr_1_2?dchild=1&pf_rd_i=7147441011&pf_rd_m=ATVPDKIKX0DER&pf_rd_p=e6aa97f3-9bc4-42c5-ac38-37844f71b469&pf_rd_r=S2F3A95JN2FDGBQ4V048&pf_rd_s=merchandised-search-9&pf_rd_t=101&qid=1624427428&s=apparel&sr=1-2"
             ]

ASIN=[]
for url in product_lst:
    idx = url.find("/dp/")
    ASIN.append(url[idx+4:idx+14])

print(ASIN)

输出

['B07R2CNSTK', 'B08SLYY1WD', 'B079QHML21', 'B089RDSML3', 'B081J8SGH7']