这应该比正则表达式快得多,您可以根据需要传递分隔符列表:
def split(txt, seps):
default_sep = seps[0]
# we skip seps[0] because that's the default separator
for sep in seps[1:]:
txt = txt.replace(sep, default_sep)
return [i.strip() for i in txt.split(default_sep)]
使用方法:
>>> split('ABC ; DEF123,GHI_JKL ; MN OP', (',', ';'))
['ABC', 'DEF123', 'GHI_JKL', 'MN OP']
性能测试:
import timeit
import re
TEST = 'ABC ; DEF123,GHI_JKL ; MN OP'
SEPS = (',', ';')
rsplit = re.compile("|".join(SEPS)).split
print(timeit.timeit(lambda: [s.strip() for s in rsplit(TEST)]))
# 1.6242462980007986
print(timeit.timeit(lambda: split(TEST, SEPS)))
# 1.3588597209964064
还有更长的输入字符串:
TEST = 100 * 'ABC ; DEF123,GHI_JKL ; MN OP , '
print(timeit.timeit(lambda: [s.strip() for s in rsplit(TEST)]))
# 130.67168392999884
print(timeit.timeit(lambda: split(TEST, SEPS)))
# 50.31940778599528