使用 Python 生成密码 [关闭]

Question

我编写了一个 Python 程序来生成密码。有一个小故障，因为它没有正确洗牌。请建议一些方法来做到这一点。还建议更好的方法。

import random 
import array

digits = ['0','1','2','3','4','5','6','7','8','9']
lowercase = ['a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z']
uppercase = ['A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z']
Symbols = ['!','@','#','$','%','*','&']

mixture = digits + lowercase + uppercase + Symbols

random_digit = random.choice(digits)
random_lowercase = random.choice(lowercase)
random_uppercase = random.choice(uppercase)
random_symbol = random.choice(Symbols) 

Password = random_digit + random_lowercase + random_uppercase + random_symbol

length = random.randint(8,12)

for x in range (length) :
    Password = Password + random.choice(mixture) 

print(Password)

Answer 1

要生成您的原始mixture，您可以利用string 中提供的字符集。另请注意，您不需要单个字符的列表，而是单个 str 也是用于此目的的可迭代序列。

>>> from string import ascii_letters as letters
>>> from string import digits as digits
>>> symbols = '!@#$%*&'
>>> mixture = digits + letters + symbols
>>> mixture
'0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ!@#$%*&'

然后要生成一些示例密码，您可以使用 random.choices 和 k 参数指定要采样的长度。

>>> import random
>>> ''.join(random.choices(mixture, k=random.randint(8,12)))
'tF6iUwki1Ir'
>>> ''.join(random.choices(mixture, k=random.randint(8,12)))
'HpPJI6@m&'
>>> ''.join(random.choices(mixture, k=random.randint(8,12)))
'$KKzoiD&'

注意random.choices 允许重复字符，如果您希望它们都是唯一的，那么random.sample 将是首选。

Answer 2

我正在研究 Cory Kramer 建议的方法。

from string import ascii_letters as letters
from string import digits as digits

symbols = '!@#$%&*'

mixture = digits + letters + symbols

import random
print('' .join(random.choice(mixture) for x in range (random.randint(8,12))))