Python split() 函数说明

Question

我对 Python 很陌生，我只是想了解一些事情。

我有一堆 txt 文件要打开，其中包含数千个单词，全部由空格分隔，我相信我在下面的代码中已经涵盖了这一点。但我只是想知道如何分解这些行分成 3 块或用户输入的一些 int 块？

来自['perfect', 'dealing', 'crave', 'stirring', 'expedition', 'alexandria', 'vanish', 'dealing', 'crave']

致[['perfect', 'dealing', 'crave'], ['stirring', 'expedition', 'alexandria'],['vanish', 'dealing', 'crave']]

甚至回到列表形式

a
b
c

TIA

word_list=[]
filename = "filename.txt"
with open(filename,"r") as file_object:
    for line in file_object:
        word_list=line.split()
        print(word_list)
    return(word_list)

Answer 1

您可以使用for i in range(0, len(word_list), 3) 以 3 的间隔遍历列表，并使用索引对原始列表进行切片

new_list = [word_list[i:i+3] for i in range(0, len(word_list), 3)]
# [['perfect', 'dealing', 'crave'], ['stirring', 'expedition', 'alexandria'], ['vanish', 'dealing', 'crave']]

Answer 2

你不是在更新word_list，而是在写它的值，它应该是这样的。

word_list=[]
filename = "filename.txt"
with open(filename,"r") as file_object:
    for line in file_object:
        word_list.append(line.split()) # notice this
        print(word_list)
    return(word_list)

sub_list_size = 3; # take from user input or as needed
output = [word_list[i: i+sub_list_size] for i in range(0, len(word_list), sub_list_size)]
print(output)

Answer 3

使用来自 itertools 配方的 grouper 构造：

def grouper(iterable, n, fillvalue=None):
    "Collect data into fixed-length chunks or blocks"
    # grouper('ABCDEFG', 3, 'x') --> ABC DEF Gxx"
    args = [iter(iterable)] * n
    return zip_longest(*args, fillvalue=fillvalue)

你的代码是：

word_list = []
n = 3
filename = "filename.txt"
with open(filename, "r") as file_object:
    for line in file_object:
        word_list.append(grouper(line.split(), n))
return word_list