【发布时间】:2013-02-24 15:08:15
【问题描述】:
我需要合计 'in' 和 'ou' 的总数,从 [a] 到 [t] 数组。
Array
(
[1] => Array
(
[in] => Array
(
[a] => 3
[b] => 0
[c] => 0
[d] => 0
[e] => 0
[f] => 0
[o] => 0
[t] => 3
)
[ou] => Array
(
[a] => 0
[b] => 0
[c] => 1
[d] => 0
[e] => 0
[f] => 0
[o] => 0
[t] => 1
)
)
[2] => Array
(
[in] => Array
(
[a] => 0
[b] => 0
[c] => 0
[d] => 0
[e] => 0
[f] => 0
[o] => 0
[t] => 0
)
[ou] => Array
(
[a] => 0
[b] => 0
[c] => 0
[d] => 1
[e] => 2
[f] => 0
[o] => 0
[t] => 3
)
)
)
以下是我如何计算总计'in'+'ou'。 然而,当谈到 'in' a,b,c,d,e,f,t 和 'ou' a,b,c,d,e,f, t.
//get day total
foreach($arr as $array){
foreach($array as $inou){
foreach(array_keys($inou) as $value){
if(isset($total[$value])){
$total[$value] += $inou[$value];
}else{
$total[$value] = $inou[$value];
}
}
}
}
输出应该类似于
in(
[a] => 3
[b] => 0
[c] => 0
...
[t] => 3
)
ou(
[a] => 0
[b] => 0
[c] => 1
[d] => 1
[e] => 2
[f] => 0
[t] => 4
)
【问题讨论】:
标签: php arrays multidimensional-array foreach sum