相同的内容值需要对多维数组求和 - 使用 PHP答案

【问题标题】：Same content value need to sum in- multidimensional array - using PHP相同的内容值需要对多维数组求和 - 使用 PHP
【发布时间】：2016-08-28 04:07:58
【问题描述】：

我有一个包含多个数组对象的数组的多维结果，需要将此结果合并到唯一值为content 和total 之和的数组的单个实例中。就像下面想要的结果。绝对感谢您的帮助。

结果集

Array
(
    [0] => Array
        (
            [response_id] => 23598
            [choice_question_detail] => Array
                (
                    [0] => Array
                        (
                            [content] => How old are your.
                            [total] => 5
                        )

                    [1] => Array
                        (
                            [content] => Stadium.
                            [total] => 4
                        )
          ),
      [1] => Array
        (
            [response_id] => 23599
            [choice_question_detail] => Array
                (
                    [0] => Array
                        (
                            [content] => How old are your.
                            [total] => 2
                        )

                    [1] => Array
                        (
                            [content] => Stadium.
                            [total] => 1
                        )
          )    
 )

期望的结果

Array
(
    [0] => Array
        (
            [content] => How old are your.
            [total] => 7
        )

    [1] => Array
        (
            [content] => Stadium.
            [total] => 5
        )
)

我当前的实现尝试做这样的事情：

$sum = array_reduce($data, function ($a, $b) {
    isset($a[$b['choice_question_detail']]) ? $a[$b['choice_question_detail']]['total'] += $b['total'] : $a[$b['total']] = $b;  
return $a;
});

【问题讨论】：

标签： php arrays multidimensional-array merge sum

【解决方案1】：

循环是这样的......有点讨厌，但它应该可以工作。

当然还有很大的优化空间，如何改进就看你自己了。

$out = array();

    foreach($var as $row) {
        foreach($row['choice_question_detail'] as $detail) {
            $flag = false;
            $numkey = -1;
            foreach($out as $key => $x) {
                if($x['content'] == $detail['content']) {
                    $flag = true;
                    $numkey = $key;
                }
            }
            if(!$flag) {
                $out[] = array(
                     'content' => $detail['content'],
                     'total' => $detail['total']          
                );
            } else {
                $out[$numkey]['total'] = $out[$numkey]['total'] + $detail['total'];
            }
        }
    }

输出是这样的

array (size=2)
   0 => array (size=2)
          'content' => string 'How old are your.' (length=17)
          'total' => int 7
   1 => array (size=2)
         'content' => string 'What is your name.' (length=18)
         'total' => int 5

【讨论】：

【解决方案2】：

没有本地方法可以做到这一点，自己写吧。

$merged = array();
foreach($responses["choice_question_detail"] as $question){
    if($merged_q=$merged[$question["content"]]){
        $merged_q["total"] += $question["total"];
    }else{
        $merged[$question["content"]] = $qeustion;
    }
}
$desired = array_values($merged);

【讨论】：