FIRAuth：访问钥匙串时发生错误（Swift 3）答案

【问题标题】：FIRAuth: An error has occurred while accessing the keychain (Swift 3)FIRAuth：访问钥匙串时发生错误（Swift 3）
【发布时间】：2017-01-26 02:06:22
【问题描述】：

我遇到了通过 Firebase 登录的问题。 Swift 2 时一切正常，但是在 XCode 将我的整个项目转换为 Swift 3 语法后，发生了错误。

这是我的登录代码：

func loginDidFinish(_ email: String, password: String, type: LoginViewController.SendType) {

        // Server call implementation here
        if type == .login {
            FIRAuth.auth()?.signIn(withEmail: email, password: password, completion: { (user, error) in

                if error != nil {
                    self.alert = UIAlertController(title: "Error", message: error?.localizedDescription, preferredStyle: .alert)
                    self.present(self.alert, animated: true, completion: nil)
                    let delay = Double(2) * Double(NSEC_PER_SEC)
                    let time = DispatchTime.now() + Double(Int64(delay)) / Double(NSEC_PER_SEC)
                    DispatchQueue.main.asyncAfter(deadline: time) { [weak self] in
                        self!.alert.dismiss(animated: true, completion: nil)
                    }
                } else {

                    _ = self.navigationController?.popViewController(animated: true)
                }
            })
        } else { // type == .SignUp
            FIRAuth.auth()?.createUser(withEmail: email, password: password, completion: { (user, error) in

                if error != nil {
                    self.alert = UIAlertController(title: "Error", message: error?.localizedDescription, preferredStyle: .alert)
                    self.present(self.alert, animated: true, completion: nil)
                    let delay = Double(2) * Double(NSEC_PER_SEC)
                    let time = DispatchTime.now() + Double(Int64(delay)) / Double(NSEC_PER_SEC)
                    DispatchQueue.main.asyncAfter(deadline: time) { [weak self] in
                        self!.alert.dismiss(animated: true, completion: nil)
                    }
                } else {

                    _ = self.navigationController?.popViewController(animated: true)
                }
            })
        }

附：当我尝试注册时一切正常。用户已创建，但popUpViewController 在这里不起作用。

附言我已经看过类似的问题"An error occurred while accessing the keychain" when signing in using Firebase，但对此一无所知。另请阅读此https://firebase.google.com/docs/auth/ios/errors。

【问题讨论】：

标签： ios firebase firebase-authentication swift3

【解决方案1】：

解决此问题的步骤：转到项目目标 -> 功能 -> 开启“钥匙串共享”

【讨论】：