为什么 elapsedtime 给我的输出为 1？ [关闭]

Question

int elapsedtime(int time1, int time2)
{
int minutes1 = ((time1/100*60)+(time1%100);
int minutes2 = ((time2/100*60)+(time2%100);
return(minutes2-minutes1);
}

/************************************************ *******************************************

do
    {
        cout << "What is your starting time? ";
        cin >> time1;
        cout << "What is your ending time? ";
        cin >> time2;

        if (time2>=time1)
        {
        cout << "Your elapsed time is " << elapsedtime <<endl;
        cout << "If you would like to enter other times?(Y/N)" <<endl;
        cin >> choice;
        }
        else
        {
        cout << "Error: Your starting time must be lower than your ending time."<<endl;
        cout << "If you would like to enter other times?(Y/N)" <<endl;
        cin >> choice;
        }
    }

每次经过的时间我都会得到 1 的输出？

Answer 1

你有

    cout << "Your elapsed time is " << elapsedtime <<endl;

你是说

    cout << "Your elapsed time is " << elapsedtime(time1, time2) <<endl;

更新

由于某种原因，

    cout << "Your elapsed time is " << elapsedtime <<endl;

在 g++ 4.7.3 下不会产生编译器错误，即使意图是使用 elapsedtime(time1, time2)。

我能够成功编译和构建：

#include <iostream>
using namespace std;

int elapsedtime(int time1, int time2)
{
   return 0;
}

int main()
{
   cout << "Your elapsed time is " << elapsedtime <<endl;
}

也许需要另一个 SO 帖子来回答这个问题，“g++ 如何不报告上述代码的错误？”。