当用户在玩我的猜谜游戏时按下回车键时，如何打印字符串？答案

【问题标题】：How can I print a string when the user presses the enter key whilst playing my guessing game?当用户在玩我的猜谜游戏时按下回车键时，如何打印字符串？
【发布时间】：2018-01-21 20:00:53
【问题描述】：

我是一名初级程序员，我创建了一个猜谜游戏，但我想合并一个字符串，当用户按下回车键时将打印该字符串，我已经尝试过，但它不起作用。（返回错误“ValueError: invalid literal for int() with base 10”）当用户按下回车键时。

如果用户不按回车键而只输入整数，程序可以正常工作。

highest = 12
lowest = 6
answer = 9


input("Press enter to play a guessing game")




guess = input("Guess a number from %d " %lowest + "to %d: " %highest)






while (int(guess) != answer) or guess == ():
    if int(guess) > answer:
        print ("Answer is lower")
    elif guess == ():
        print ("That's not valid") 




    else:
        print("Answer is higher")



guess = input("Guess again ")

print ("Correct!!")

【问题讨论】：

guess == () 永远不会是True。
@cᴏʟᴅsᴘᴇᴇᴅ 好吧，如果我放类似
@coldspeed str(guess) == ("") 这行得通吗？
是的，会的。

标签： python input enter

【解决方案1】：

import random
a = int
b = int
c= int
def guessing():

      guess = int(input("guess an no between 1 to 10: "))
      c = random.randrange(1,11)
      print("answer is",c)
      if (guess == c):
            print("correct guess")
      elif(guess>c):
            print("higher")
      else:
            print("lower")

d=input("\n\n Y TO START \n n to exit\n")
if (d == "y" or d == "Y"):
      guessing()
elif(d =="n" or d == "N"):
      print("exit")

【讨论】：