在类属性中分配空对象？

Question

将占位符（空对象）分配给类属性的正确方法是什么？

例子：

class something {

    public $my_object = object; // ???

    public function __construct() {

        //create some object, via some function...

        $this->my_object = $some_object;
    }

}

Answer 1

可能是这样的：

class something {

    public $my_object;

    public function __construct() {

        $some_object = new StdClass();

        $this->my_object = $some_object;
    }

}

测试：

$obj = new something();
var_dump($obj);

输出：

object(something)#1 (1) {
  ["my_object"]=>
  object(stdClass)#2 (0) {
  }
}