【发布时间】：2020-02-11 02:43:20
【问题描述】：
当我尝试检索属性的值并包含参数时，我收到“对象不可调用”错误消息。
当我获得该值时，我想选择将“刷新”指定为 True，以强制从我的主机重新学习该值，而不是使用存储在我的变量中的值。例如，如果我说a = x.host_name(refresh=True)，我希望从主机中检索主机名，而不是从变量_host_name 中提取。
#!/usr/local/bin/python3.7
import netaddr
"""
test.py - Used for testing
"""
class Host():
"""
Represents a Host device
Attributes:
host_name: str
Name of host
manage_address: IP
Managment IP address of the host
"""
def __init__(self, host_name="", manage_address=netaddr.IPAddress("0.0.0.0")):
"""
The constructor for the Host class.
Parameters:
host_name: str
Host name of the host
manage_address: ip
Management IP address of this host
"""
self._host_name = host_name
self._manage_address = manage_address
@property
def host_name(self, refresh=False):
"""
The host name configured for this host device
Paramters:
refresh: bool
Should we relearn the hostname if we already know it?
Returns: str
Host name defined on the host
"""
if refresh:
# TODO: Get hostname from the host
pass
return self._host_name
@host_name.setter
def host_name(self, host_name):
"""
Set the host name of the host
Parameters
host_name: str
The host name to configure on the host
Returns: None
"""
self._host_name = host_name
@property
def manage_address(self, refresh=False):
"""
The IP address to manage the host
Paramters:
refresh: bool
Should we relearn the IP address if we already know it?
Returns: IP
Management IP address of the host
"""
if refresh:
# TODO: Get management IP address from the host
pass
return self._manage_address
@manage_address.setter
def manage_address(self, manage_address):
"""
Set the management IP address of the host
Parameters
manage_address: IP
The management IP address of the host
Returns: None
"""
self._manage_address = manage_address
if __name__ == '__main__':
# A host object
h = Host()
h.host_name = "myhost.com"
print(h.host_name) # Works
print(h.host_name(refresh=True)) # str object is not callable error
print((str(h.manage_address(refresh=True)))) # IPAddress object is not callable error
我的猜测是我在从属性中获取值时不允许传递参数...但是如果是这种情况，我如何有条件地获取值？
【问题讨论】：
-
您不能将参数传递给属性访问，这是没有意义的。正如错误告诉您的那样，您最终会尝试调用属性返回的值。如果您需要参数，请将其设为常规方法。
-
@jonrsharpe 我虽然是这样，但我不明白如何使用常规方法创建等效的 getter 和 setter。
-
...移除装饰器并在 get_ 和 set_ 前添加？
标签： python parameters properties setter getter