如何反序列化来自 MYSQL 的查询结果？答案

【问题标题】：How can I unserialize my query results from MYSQL?如何反序列化来自 MYSQL 的查询结果？
【发布时间】：2016-01-04 13:49:01
【问题描述】：

我的代码现在的样子

 $client = $_GET['client_number_search'];
 

$sql=("SELECT * FROM tobytemp.fcl_reports WHERE client_number = '" . $client . "'");

$result = $dbLink->query($sql);




$arr = array();
	
while ($r = $result->fetch_object()) {
   $temp=[
      "client_number" => $r->client_number,
      "client_name" => $r->client_name,
      "service" => unserialize($r->service),
      "volume" => $r->volume,
      "deliver_point" => $r->deliver_point,
      "port_orgin" => $r->port_orgin,
      "size" => $r->size
   ];

    array_push($arr,$temp);

}
	
	echo json_encode($arr);





/* ERROR

Request Method:GET
Status Code:500 Internal Server Error



*/

像这样填充在我的表中的当前数据 -

service - a:2:{i:0;s:6:"Inport";i:1;s:6:"Export";}

我希望它显示为 -

Service-
Import
Export

（我不能在我的clientreports.html 页面上使用 PHP，因为我想稍后将其用作电话间隙的应用程序）。

AJAX 调用 (clientreports.html)

<script type="text/javascript">
    $("#show_clientx").click(function(e) {

        $("table#client_profile").empty();

        $.ajax({
            url: "http://cmlsys/toby/client_profile.php?client_number_search=" + $("#client_number").val(),
            type: "GET",
            dataType: "json",
            success: function(html) {

                //  $("table#client_profile").append('<tr><th>Client Number</th><th>Client Name</th><th>Address</th></tr>');

                jQuery.each(html, function(key, value) {

                    $("table#client_profile").append('<tr><td>' + value.client_number + '</td><td> client_name - ' + value.client_name + '</td></tr><tr></br><td>service - ' + value.service + '</td></br><td>size - ' + value.size + '</td></br><td>volume - ' + value.volume + '</td></br><td>deliver_point -' + value.deliver_point + '</td></br><td>port_orgin - ' + value.port_orgin + '</td></tr>');

                });

            },
            error: function(e) {
                console.log("Error: " + e);
            }
        });
    });
</script>

TO - client_profile.php

$client = $_GET['client_number_search'];

$sql = ("SELECT * FROM tobytemp.fcl_reports WHERE client_number = '".$client.
    "'");

$result = $dbLink - > query($sql);            

$arr = array();

while ($r = $result - > fetch_object()) {

    array_push($arr, array("client_number" => $r - > client_number, "client_name" => $r - > client_name, "service" => $r - > service, "size" => $r - > size, "volume" => $r - > volume, "deliver_point" => $r - > deliver_point, "port_orgin" => $r - > port_orgin));

}

echo json_encode($arr);

请帮忙

【问题讨论】：

标签： javascript php jquery ajax serialization

【解决方案1】：

在 php 中使用反序列化

例如

$demo=unserialize('a:2:{i:0;s:6:"Inport";i:1;s:6:"Export";}');

echo json_encode($demo);

在您的代码中，您可以更改 while 循环

while ($r = $result->fetch_object()) {
   $temp=[
      "client_number" => $r->client_number,
      "client_name" => $r->client_name,
      "service" => unserialize($r->service),
      "volume" => $r->volume,
      "deliver_point" => $r->deliver_point,
      "port_orgin" => $r->port_orgin,
      "size" => $r->size
   ];

    array_push($arr,$temp);

}

【讨论】：

什么都不显示。我试过这个--- $US=unserialize($arr); echo json_encode($US);
不，不要那样做，我只编辑你的代码取消序列化$r - > service
（感谢您的帮助）我在使用您的 while 循环时收到 500 内部服务器错误。
它是一个空格，我将其删除。你现在可以试试
请不要放弃我 :) @DeveloperH

【解决方案2】：

$arr = array();

while ($r = $result->fetch_object()){
    array_push($arr, array (
    "client_number" => $r ->client_number, 
    "client_name" => $r->client_name, 
    "service" => unserialize($r ->service),
    "size" => unserialize($r ->size),
    "volume" => unserialize($r ->volume),
    "deliver_point" => unserialize($r ->deliver_point),
    "port_orgin" => unserialize($r ->port_orgin))
    );

}



echo json_encode($arr);

【讨论】：