【发布时间】：2013-05-31 09:09:59
【问题描述】：
我想开始使用 Spring MVC，但无法调整一个简单的示例。我只想将一个参数从一个 jsp 传递给另一个，但是有错误：
HTTP 状态 404 - /controller/results.jsp 类型状态报告消息 /controller/results.jsp 描述 请求的资源 (/controller/results.jsp) 不可用。 Apache Tomcat/7.0.12
我的 web.xml 代码：
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring/root-context.xml</param-value>
</context-param>
<!-- Creates the Spring Container shared by all Servlets and Filters -->
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<!-- Processes application requests -->
<servlet>
<servlet-name>appServlet</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring/appServlet/servlet-context.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>appServlet</servlet-name>
<url-pattern>/home</url-pattern>
</servlet-mapping>
Servlet-context.xml
<!-- DispatcherServlet Context: defines this servlet's request-processing infrastructure -->
<!-- Enables the Spring MVC @Controller programming model -->
<annotation-driven />
<!-- Handles HTTP GET requests for /resources/** by efficiently serving up static resources in the ${webappRoot}/resources directory -->
<resources mapping="/resources/**" location="/resources/" />
<!-- Resolves views selected for rendering by @Controllers to .jsp resources in the /WEB-INF/views directory -->
<beans:bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<beans:property name="prefix" value="/WEB-INF/views/" />
<beans:property name="suffix" value=".jsp" />
</beans:bean>
<context:component-scan base-package="edu.demidov.controller" />
</beans:beans>
Controller.java
@Controller
public class HomeController extends HttpServlet{
private static final long serialVersionUID = 4825408935018763217L;
private static final Logger logger = LoggerFactory.getLogger(HomeController.class);
EducationDaoInterface educationDaoIntfc;
@RequestMapping(value="/home", method=RequestMethod.GET)
public ModelAndView firstActionPage() {
return new ModelAndView("home");
}
@RequestMapping(value = "/result.jsp", method=RequestMethod.GET)
public String SecondActionPage(@RequestParam String firstname, Model model) throws IOException {
model.addAttribute("myname", firstname);
return "result";
}
结果.jsp
<%@ page language="java" contentType="text/html; charset=UTF-8"
pageEncoding="UTF-8"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>Insert title here</title>
</head>
<body>
Hello form result.jsp
First name: ${myname}
</body>
</html>
Home.jsp
<%@ page language="java" contentType="text/html; charset=UTF-8"
pageEncoding="UTF-8"%>
<%@ taglib prefix="c" uri="http://java.sun.com/jsp/jstl/core"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>Insert title here</title>
</head>
<body>
<form name="myform" action="<c:url value="/results.jsp"/>" method="GET">
<input type="text" name="firstname"/>
<input type="submit"/>
</form>
</body>
</html>
谢谢。
【问题讨论】：
-
尝试在
/* 上更改映射，在您的情况下，提交 url 后未使用 spring mvc 处理，您会收到错误 -
非常感谢乔治的帮助。对，当我改变它时，它似乎是工作。只是我对什么是 url-pattern 感到困惑。我认为默认情况下它会在我在服务器上运行时映射我的请求，并且应该使用此 url-pattern 将我引导到我的第一个 RequestMapping 方法。但是如何使用表单在两个页面之间进行操作。我所做的是把 localhost:8080/controller/result?firstname=hello 放到我的 jsp 中，但我想使用从一页到另一页的操作。
标签： spring model-view-controller servlets spring-mvc