【发布时间】:2017-10-01 01:04:00
【问题描述】:
我有两个 Django 视图,一个加载表单集,一个提交表单集。这是为了避免表单重新提交或在 POST 后必须更改为不同的视图。提交后,我重定向回加载表单集的视图。但我无法让 URLs/reverse 工作。
这是我的观点和网址
def view(request, model1_id):
#load formsets
#pass information to submit view
request.session['model1_session'] = int(model1_id)
return render(request, 'app/view.html')
def view_submit(request):
#get the session
model1_object = request.session.get('model1_session')
...
if request.method == 'POST':
#save formset
#error!!!!
return HttpResponseRedirect(reverse("app:view", kwargs={"model1_id": "model1_object"}))
url(r'^(?P<model1_id>[0-9]+)/model1/something/$', views.view, name='view' ),
url(r'^model1/something/submit/$', views.view_submit, name='view_submit' ),
但是当我按下提交时,一切都保存得很好,但是反过来就不行了....
Internal Server Error: /app/model1/something/submit/
Traceback (most recent call last):
File "/Library/Python/2.7/site-packages/django/core/handlers/base.py", line 149, in get_response
response = self.process_exception_by_middleware(e, request)
File "/Library/Python/2.7/site-packages/django/core/handlers/base.py", line 147, in get_response
response = wrapped_callback(request, *callback_args, **callback_kwargs)
File "/Users/username/Documents/Database/project/app/views.py", line 412, in view_submit
return HttpResponseRedirect(reverse("app:view", kwargs={"model1_id": "model1_object"}))
File "/Library/Python/2.7/site-packages/django/core/urlresolvers.py", line 600, in reverse
return force_text(iri_to_uri(resolver._reverse_with_prefix(view, prefix, *args, **kwargs)))
File "/Library/Python/2.7/site-packages/django/core/urlresolvers.py", line 508, in _reverse_with_prefix
(lookup_view_s, args, kwargs, len(patterns), patterns))
NoReverseMatch: Reverse for 'view' with arguments '()' and keyword arguments '{'model1_id': 'model1_object'}' not found. 1 pattern(s) tried: [u'app/(?P<model1_id>[0-9]+)/model1/something/$']
我不明白为什么它不接受 kwargs?
class Model1(models.Model):
...
def __str__(self):
return unicode(self.id) or u''
def get_absolute_url(self):
#I think this is the problem... but I don't know how to solve it...
return reverse('app:view', kwargs={'id': self.id})
...帮助...
【问题讨论】:
-
reverse("app:view", kwargs={"model1_id": "model1_object"}发生错误 -
我没有看到任何类似于
'app:model1'名称模式的网址。请提供完整的urls.py -
@SardorbekImomaliev 啊,我在尝试简化代码时错过了这一点。现在应该使模式有意义吗?
-
另请注意,您的
model1_id应该是一个数字而不是字符串,因为您的网址格式中有[0-9]+
标签: python django url redirect arguments