逆时针旋转矩阵 M*N 的每个环

Question

我无法逆时针旋转M*N 矩阵。我的代码对3*3 矩阵正常工作，但是当我尝试任何其他情况时它不起作用假设我正在为4*4 矩阵做它，那么只有外部元素在旋转，内部 4 个元素（即 6,7,10 ,11) 不旋转。我的输入是 1-16 个数字作为4*4 矩阵：

{ {1, 2, 3, 4}, {5, 6, 7, 8}, {9, 10, 11, 12}, {13, 14, 15, 16} }

static void antiRotateMatrix(int m, int n, int mat[][]) {
    int row = 0, col = n - 1;
    int prev, curr;
    while (row < m && col < n) {
        if (row + 1 == m || col - 1 == 0) {
            break;
        }
        prev = mat[row + 1][col];
        for (int i = col; i >= 0; i--) {
            curr = mat[row][i];
            mat[row][i] = prev;
            prev = curr;
        }
        row++;

        for (int i = row; i < m; i++) {
            curr = mat[i][0];
            mat[i][0] = prev;
            prev = curr;
        }
        n--;

        if (row < m) {
            for (int i = n - 2; i <= col; i++) {
                curr = mat[m - 1][i];
                mat[m - 1][i] = prev;
                prev = curr;
            }
        }
        m--;
        if (col <= n) {
            for (int i = m - 1; i >= row; i--) {
                curr = mat[i][col];
                mat[i][col] = prev;
                prev = curr;
            }
        }
        col++;
    }
    for (int i = 0; i <= 3; i++) {
        for (int j = 0; j <= 3; j++)
            System.out.print(mat[i][j] + " ");
        System.out.print("\n");
    }
}

对于4*4，我应该得到

{{2,3,4,8},{1,7,11,12},{5,6,10,16},{9,13,14,15}}

但我得到了

{{2,3,4,8},{1,6,7,12},{5,10,11,16},{9,13,14,15}}

Answer 1

逆时针旋转每一层M*N的矩阵元素：

for z in range(r):#r = n times to rotate your element of each layer
    top = 0
    bottom = len(matrix)-1

    left = 0
    right = len(matrix[0])-1

    while left < right and top < bottom: # anticlockwise rotation of each layer.
        prev = matrix[top+1][right]
        for i in range(right,left-1,-1):
            curr = matrix[top][i]
            matrix[top][i]= prev
            prev =curr
        top += 1
        for i in range(top,bottom+1):
            curr = matrix[i][left]
            matrix[i][left]=prev
            prev=curr
        left += 1
        for i in range(left,right+1):
            curr =matrix[bottom][i]
            matrix[bottom][i]=prev
            prev = curr
        bottom -=1
        for i in range(bottom,top-1,-1):
            curr = matrix[i][right]
            matrix[i][right]=prev
            prev = curr
        right -=1

顺时针转至https://www.geeksforgeeks.org/rotate-matrix-elements/

希望你可以把这个#python代码应用到#java，逻辑是一样的。或者在hackerrank中选择python。