【问题标题】:How can I do both zoom and rotate on an inkcanvas?如何在 inkcanvas 上同时进行缩放和旋转?
【发布时间】:2011-08-10 08:49:02
【问题描述】:

使用以下 XAML:

<Grid x:Name="grid" Background="LightBlue" ClipToBounds="True">
        <Grid.RowDefinitions>
            <RowDefinition Height="*" />
        </Grid.RowDefinitions>
    <Viewbox x:Name="imgViewbox" >
                <InkCanvas Grid.Row="0" Name="inkCanvas" Background="Red" >
                <Image Source="Images/pic.png" HorizontalAlignment="Left" x:Name="imgObject" VerticalAlignment="Top"  />
                <Label>Testing</Label>
                </InkCanvas>
    </Viewbox>
</Grid>

我正在尝试围绕图像中心旋转并使用滚轮鼠标进行缩放。我已经设置了这个转换组和事件:

public MainWindow() {

    InitializeComponent();
    DataContext = new MainWindowViewModel();

    transformGroup = new TransformGroup();
    scaleTransform = new ScaleTransform();
    rotateTransform = new RotateTransform();
    translateTransform = new TranslateTransform();
    transformGroup.Children.Add(rotateTransform);
    transformGroup.Children.Add(scaleTransform);
    transformGroup.Children.Add(translateTransform);

    imgViewbox.RenderTransform = transformGroup;

    imgViewbox.MouseWheel += ImageViewboxMouseWheel;
}

旋转很简单:

void Rotate(object sender, RoutedEventArgs e) {
    //imgViewbox.RenderTransformOrigin = new Point(0.5,0.5);
    rotateTransform.Angle += 90;
}

但是缩放正在做各种奇怪的事情,在屏幕上跳跃。缩放的代码在这里:

void ImageViewboxMouseWheel(object sender, MouseWheelEventArgs e) {
    //imgViewbox.RenderTransformOrigin = new Point(0, 0);
    double zoomFactor = DefaultZoomFactor;
    if (e.Delta <= 0) zoomFactor = 1.0 / DefaultZoomFactor;
    // DoZoom requires both the logical and physical location of the mouse pointer
    var physicalPoint = e.GetPosition(imgViewbox);
    if (transformGroup.Inverse != null) {
        DoZoom(zoomFactor, transformGroup.Inverse.Transform(physicalPoint), physicalPoint);
    }
    else {
        throw new ArgumentException("Missing Inverse");
    }

    //Set the center point of the ScaleTransform object to the cursor location.
    scaleTransform.CenterX = e.GetPosition(imgViewbox).X;
    scaleTransform.CenterY = e.GetPosition(imgViewbox).Y;
    Debug.WriteLine(string.Format("IVMW Center {0},{1}", scaleTransform.CenterX, scaleTransform.CenterY));
}

public void DoZoom(double deltaZoom, Point mousePosition, Point physicalPosition) {
    double currentZoom = scaleTransform.ScaleX;
    currentZoom *= deltaZoom;

    translateTransform.X = -1*(mousePosition.X*currentZoom - physicalPosition.X);
    translateTransform.Y = -1*(mousePosition.X*currentZoom - physicalPosition.Y);
    scaleTransform.ScaleX = currentZoom;
    scaleTransform.ScaleY = currentZoom;
}

我已经尽可能多地删除了动画等。希望只留下关键部分。我认为主要问题是 scaleTransform.Center[X|Y] 因为即使我尝试在同一个位置单击,返回的数字也遍布整个象限。 RenderTransformOrigin 似乎与中心位置没有任何区别,但我知道我需要它围绕中心旋转。

我做错了什么?

【问题讨论】:

    标签: c# wpf zooming rotation mousewheel


    【解决方案1】:

    您需要抵消因在 TranslateTransform 中更改 ScaleTranform 的 CenterX/Y 而获得的跳跃,这是我写的平移和缩放控件的 sn-p:

    private void This_MouseWheel(object sender, MouseWheelEventArgs e)
    {
        if (IsZoomEnabled)
        {
            Point cursorPos = e.GetPosition(this);
            Point newCenter = _scaleT.Inverse.Transform(_translateT.Inverse.Transform(cursorPos));
            Point oldCenter = new Point(_scaleT.CenterX, _scaleT.CenterY);
            Vector oldToNewCenter = newCenter - oldCenter;
            _scaleT.CenterX = newCenter.X;
            _scaleT.CenterY = newCenter.Y;
            _translateT.X += oldToNewCenter.X * (_scaleT.ScaleX - 1.0);
            _translateT.Y += oldToNewCenter.Y * (_scaleT.ScaleY - 1.0);
            ...
    

    希望您可以根据自己的代码进行调整。计算新中心的位置可能需要考虑 RotateTransform。

    【讨论】:

    • 我把它放进去,我想我明白为什么这是必要的,但是当我最大化我的窗口并滚动屏幕中心的滚轮时,我看到 oldCenter 的 CenterY 是负数。这似乎不对。知道为什么会这样吗?
    • 我在哪里写 e.GetPosition(this) 你可能需要传递对 InkCanvas 或其他适当控件/容器的引用,也许这会解决它。
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