无效转换错误？我如何克服这个错误？

Question

我想用它们的位置 (0,1,2,3,4) 初始化数组中的 5 个对象。这只是语法错误吗？我觉得我没有正确使用指针。请帮忙！在有人将其标记为重复之前，我知道它与其他几个问题相似，但他们的解决方案似乎都不适合我。除非我做错了，我承认这是可能的，但这就是我在这里的原因。

输出：

代码：

#include <iostream>

using namespace std;

class CuteRobot{
private:
    int position; //x-axis position
    
public:
    CuteRobot(){};
    
    CuteRobot(int p){ //initialize default position
    position = p;
}

    void getPosition(){ //getter
    cout << "position: "<< position;
}

    CuteRobot& move(int steps){ //Positive number for forward motion, negative number for backward motion.  
                                //Ideally, implement function chaining here, CuteRobot&  move(int steps);  
    if(steps >=1){
        position = position + steps;
    } else {
        position = position - steps;
    }
    return *this;
}

    void meet(CuteRobot* cr){ //The function takes a pointer parameter, calculates the steps value when the cr object meets this objectect, 
                              // assuming this object stands still, and use move() function to bring cr object to this object position.
        int steps = (this->position) - (cr->position);
        cr->move(steps);
    }
};

int main()
{
    CuteRobot* cr[5] ={0,1,2,3,4}; // array of five CuteRobot objects.
    
    for(int i =1; i < 5; i++){ //loop through the array and use meet() method to bring every robots to zero position 
                                //(where the first robot stands)?
        cr[i]->meet(cr[0]);
        cr[i]->getPosition();
    }
    return 0;
}

Answer 1

你可能是指它们的数组（不是指向一个的指针）：

CuteRobot cr[5] = {0,1,2,3,4};

然后使用对象而不是指针表示法：

 cr[i].meet(cr);
 ...