Python wget一次下载多个文件

Question

寻找一次下载多个文件的干净的 Python Wget 解决方案。

网址将始终相同：

https://example.com/

到目前为止，我可以做到这一点：

import wget

print('Beginning file download with wget module')
url = 'https://example.com/new_folder/1.jpg'
wget.download(url)

但我还需要下载 -2.jpg、-3.jpg、-4.jpg、-5.jpg 并将 NWZV1WB 重命名为 NEWCODE-1.jpg、NEWCODE -2.jpg...

---

我还需要下载文件夹中的所有 content(22).jpg 文件并将本地文件夹重命名为 NEWCODE 之类的名称，但保留文件的原始名称

这里的网址也总是一样的：

import wget

print('Beginning file download with wget module')
url = 'https://example.com/big/1.jpg' #there's 18 jpg inside
wget.download(url)

什么是最好的，wget（找不到很多关于的文章）或请求？任何帮助表示赞赏。

Answer 1

例如：

import wget
import os
import multiprocessing

def run_process(url, output_path):
    wget.download(url, out=output_path)
    # TODO: you can write your rename logic at here using os.rename


if __name__ == '__main__':
    cpus = multiprocessing.cpu_count()
    max_pool_size = 4
    pool = multiprocessing.Pool(cpus if cpus < max_pool_size else max_pool_size)
    base_dir = os.path.dirname(os.path.abspath(__file__))
    target = "NEWCODE"
    prefix_list = ["NWZV1WB", "AWU3JAD", "NW96MRD"]
    download_list = []
    name_list = list(range(1, 23))
    name_list.extend(["zoom_side", "zoom_sole", "zoom_side-thumb"])
    for prefix in prefix_list:
        path = os.path.join(base_dir, prefix)
        if not os.path.exists(path):
            os.mkdir(path)
        if not os.path.isdir(path):
            exit()
        for name in name_list:
            download_list.append(['https://img2.tennis-warehouse.com/360/{p}/{n}.jpg'.format(n=name, p=prefix), path])

    for url, path in download_list: # change here to download other files
        print('Beginning file download with wget module {n}'.format(n=url))
        pool.apply_async(run_process, args=(url, path, ))
    # add your code here to download other files
    pool.close()
    pool.join()
    print("finish")