查询 JSONB 对象数组

Question

我做了一个 DB Fiddle，看看这张桌子看起来像 https://www.db-fiddle.com/f/4jyoMCicNSZpjMt4jFYoz5/3382

表格中的数据如下所示

[
    {
        "id": 1,
        "form_id": 1,
        "questionnaire_response": [
            {
                "id": "1",
                "title": "Are you alive?",
                "value": "Yes",
                "form_id": 0,
                "shortTitle": "",
                "description": ""
            },
            {
                "id": "2",
                "title": "Did you sleep good?",
                "value": "No",
                "form_id": 0,
                "shortTitle": "",
                "description": ""
            },
            {
                "id": "3",
                "title": "Whats favorite color(s)?",
                "value": [
                    "Red",
                    "Blue"
                ],
                "form_id": 0,
                "shortTitle": "",
                "description": ""
            }
        ]
    },
    {
        "id": 2,
        "form_id": 1,
        "questionnaire_response": [
            {
                "id": "1",
                "title": "Are you alive?",
                "value": "Yes",
                "form_id": 0,
                "shortTitle": "",
                "description": ""
            },
            {
                "id": "2",
                "title": "Did you sleep good?",
                "value": "Yes",
                "form_id": 0,
                "shortTitle": "",
                "description": ""
            },
            {
                "id": "3",
                "title": "Whats favorite color(s)?",
                "value": "Black",
                "form_id": 0,
                "shortTitle": "",
                "description": ""
            }
        ]
    },
    {
        "id": 3,
        "form_id": 1,
        "questionnaire_response": [
            {
                "id": "1",
                "title": "Are you alive?",
                "value": "Yes",
                "form_id": 0,
                "shortTitle": "",
                "description": ""
            },
            {
                "id": "2",
                "title": "Did you sleep good?",
                "value": "No",
                "form_id": 0,
                "shortTitle": "",
                "description": ""
            },
            {
                "id": "3",
                "title": "Whats favorite color(s)?",
                "value": [
                    "Black",
                    "Red"
                ],
                "form_id": 0,
                "shortTitle": "",
                "description": ""
            }
        ]
    }
]

我有一个问题select * from form_responses,jsonb_to_recordset(form_responses.questionnaire_response) as items(value text, id text) where (items.id = '3' AND items.value like '%Black%');

但不能像select * from form_responses,jsonb_to_recordset(form_responses.questionnaire_response) as items(value text, id text) where (items.id = '3' AND items.value like '%Black%') AND (items.id = '2' AND items.value like '%Yes%');那样做多个对象

对象中的值字段也可以是数组或单个值.. 不可预测.. 我觉得我很接近但也不确定我是否首先使用了正确的查询。

任何帮助将不胜感激！

编辑

select * from form_responses where(
  questionnaire_response @> '[{"id": "2", "value":"No"},{"id": "3", "value":["Red"]}]')

似乎可行，但不确定这是否是最好的方法

Answer 1

您当前的查询每项返回一个结果行。这些行都没有id = 3 和id = 2。如果您的目标是选择整个表单响应，则需要使用子查询（或者更确切地说，其中两个）：

SELECT *
FROM form_responses
WHERE EXISTS(
    SELECT *
    FROM jsonb_to_recordset(form_responses.questionnaire_response) as items(value text, id text)
    WHERE items.id = '3'
      AND items.value like '%Black%'
  )
  AND EXISTS(
    SELECT *
    FROM jsonb_to_recordset(form_responses.questionnaire_response) as items(value text, id text)
    WHERE items.id = '2'
      AND items.value like '%Yes%'
  );

或者

SELECT *
FROM form_responses
WHERE (
    SELECT value
    FROM jsonb_to_recordset(form_responses.questionnaire_response) as items(value text, id text)
    WHERE items.id = '3'
  ) like '%Black%'
  AND (
    SELECT value
    FROM jsonb_to_recordset(form_responses.questionnaire_response) as items(value text, id text)
    WHERE items.id = '2'
  ) like '%Yes%';

更好的选择是使用json path 查询：

SELECT *
FROM form_responses
WHERE questionnaire_response @@ '$[*]?(@.id == "1").value == "Yes"'
  AND questionnaire_response @@ '$[*]?(@.id == "3").value[*] == "Black"'
-- in one:
SELECT *
FROM form_responses
WHERE questionnaire_response @@ '$[*]?(@.id == "1").value == "Yes" && $[*]?(@.id == "3").value[*] == "Black"'

[*] 甚至对于有时字符串有时数组值具有正确的语义。如果您知道具有这些 id 的项目的索引，您甚至可以简化为

SELECT *
FROM form_responses
WHERE questionnaire_response @@ '$[0].value == "Yes" && $[2].value[*] == "Black"'

^{(dbfiddle demo)}