在 SWIFT 中绘制圆弧进度

Question

我想创建一个带有切片的循环进度，其中每个切片都是一个弧。

我的代码基于这个答案： Draw segments from a circle or donut

但我不知道如何将它复制并旋转 10 次。 我想按照进度变量（百分比）为它着色。

编辑：我想要这样的东西

请帮忙

问候

Answer 1

您可以使用圆形路径并设置 strokeStart 和 StrokeEnd。像这样的：

let circlePath = UIBezierPath(ovalInRect: CGRect(x: 200, y: 200, width: 150, height: 150))
var segments: [CAShapeLayer] = []
let segmentAngle: CGFloat = (360 * 0.125) / 360

for var i = 0; i < 8; i++ {
    let circleLayer = CAShapeLayer()
    circleLayer.path = circlePath.CGPath

    // start angle is number of segments * the segment angle
    circleLayer.strokeStart = segmentAngle * CGFloat(i)

    // end angle is the start plus one segment, minus a little to make a gap
    // you'll have to play with this value to get it to look right at the size you need
    let gapSize: CGFloat = 0.008
    circleLayer.strokeEnd = circleLayer.strokeStart + segmentAngle - gapSize

    circleLayer.lineWidth = 10
    circleLayer.strokeColor = UIColor(red:0,  green:0.004,  blue:0.549, alpha:1).CGColor
    circleLayer.fillColor = UIColor.clearColor().CGColor

    // add the segment to the segments array and to the view
    segments.insert(circleLayer, atIndex: i)
    view.layer.addSublayer(segments[i])
}