C# 中的质因数

Question

我想在 C# 2005 中创建一个计算给定输入的素数的程序。我想使用基本和最简单的东西，不需要为它创建一个方法，也不需要数组等等。只是简单的模数。有什么代码可以满足我的愿望吗？

这是查找简单因子的代码，我需要修改此代码以计算素因子

class Program
{
    static void Main(string[] args)
    {
        int a, b;
        Console.WriteLine("Please enter your integer: ");
        a = int.Parse(Console.ReadLine());
        for (b = 1; b <= a; b++)
        {
            if (a % b == 0)
            {
                Console.WriteLine(b + " is a factor of " + a);
            }
        }
        Console.ReadLine();



    }
}

Answer 1

int a, b;
Console.WriteLine("Please enter your integer: ");
a = int.Parse(Console.ReadLine());

for (b = 2; a > 1; b++)
    if (a % b == 0)
    {
        int x = 0;
        while (a % b == 0)
        {
            a /= b;
            x++;
        }
        Console.WriteLine($"{b} is a prime factor {x} times!");
    }
Console.WriteLine("Th-Th-Th-Th-Th-... That's all, folks!");

Answer 2

public static List<int> Generate(int number)
{
    var primes = new List<int>();

    for (int div = 2; div <= number; div++)
        while (number % div == 0)
        {
            primes.Add(div);
            number = number / div;
        }
    
    return primes;
}

如果你想了解开发步骤可以watch video here。

Answer 3

因为除数永远不会大于数字的平方根，所以你可以做得更好。

 for(int div = 2; div <= Math.Sqrt(number); div++)

Answer 4

此版本将所有因素作为明确的公式列出：

static void Main(string[] args)
    {
        Console.WriteLine("Please enter your integer (0 to stop): ");

        int a = int.Parse(Console.ReadLine());
        while(a>0)
        {
            List<int> primeFactors = PrimeFactors(a);
            LogFactorList(primeFactors);
            a = int.Parse(Console.ReadLine());
        }
        Console.WriteLine("Goodbye.");
    }


    /// <summary>
    /// Find prime factors
    /// </summary>
    public static List<int> PrimeFactors(int a)
    {
        List<int> retval = new List<int>();
        for (int b = 2; a > 1; b++)
        {               
            while (a % b == 0)
            {
                a /= b;
                retval.Add(b);
            }               
        }
        return retval;
    }

    /// <summary>
    /// Output factor list to console
    /// </summary>
    private static void LogFactorList(List<int> factors)
    {
        if (factors.Count == 1)
        {
            Console.WriteLine("{0} is Prime", factors[0]);
        }
        else
        {
            StringBuilder sb = new StringBuilder();
            for (int i = 0; i < factors.Count; ++i)
            {
                if (i > 0)
                {
                    sb.Append('*');
                }
                sb.AppendFormat("{0}", factors[i]);
            }
            Console.WriteLine(sb.ToString());
        }
    }

Answer 5

试试这段代码（我在这段代码中加入了各种解决方案）。虽然，插值不是在 2005 年（我想是这样......）

所以，无论如何，试试这个：

// C# Program to print all prime factors 
using System; 

namespace prime
{
    public class Prime
    { 

        public static void PrimeFactors(int n)
        {
            Console.Write($"Prime Factors of {n} are:  ");

            // Prints all the numbers of 2  
            while (n % 2 == 0)
            {
                Console.Write("2 ");
                n /= 2;
            }

            // As no 2 can be further divided, this probably means that n
            // is now an odd number
            for(int i = 3; i <= Math.Sqrt(n); i += 2)
            {
                while (n % i == 0)
                {
                    Console.Write($"{i} ");
                    n /= i;
                }
            }

            // This is for case if n is greater than 2
            if (n > 2)
            {
                Console.Write($"{n} ");
            }

        }

        // Prompts user to give Input to number and passes it on 
        // the PrimeFactors function after checking its format
        public static void RunPrimeFactors()
        {
            Console.Write("Enter a number: ");
            if (int.TryParse(Console.ReadLine(), out int n))
            {
                PrimeFactors(n);
            }
            else
            {
                Console.WriteLine("You entered the wrong format");
            }

        }
        // Driver Code 
        public static void Main()
        {
            RunPrimeFactors();
        }

    }
}

Answer 6

using static System.Console;

namespace CodeX
{
    public class Program
    {
        public static void Main(string[] args)
        {
            for (int i = 0; i < 20; i++)
            {
                if (IsPrime(i))
                {
                    Write($"{i} ");
                }
            }
        }

        private static bool IsPrime(int number)
        {
            if (number <= 1) return false;  // prime numbers are greater than 1

            for (int i = 2; i < number; i++)
            {
                // only if is not a product of two natural numbers
                if (number % i == 0)       
                    return false;
            }

            return true;
        }
    }
}