每个 subplotSpec 的标题（子图中的子图）

Question

我想制作一个具有 2x2 外部布局和这些 2x3 布局中的每一个的地块。我设法使用 gridSpec 让一切正常工作，但我似乎无法为每个 subplotSpec 分配一个标题（有 2x2 subplotSpec）。

Row titles for matplotlib subplot 这原则上应该给我解决方案，但我想知道是否有办法使用gridSpec而不是隐藏白框来实现这一点。

import matplotlib.pyplot as plt
import matplotlib.gridspec as gridspec

netdict = ["chain","V"]
sigdict = ["no","with"]

fig = plt.figure(figsize=(10, 8))
outer = gridspec.GridSpec(2, 2, wspace=0.3, hspace=0.3) # make a 2x2 outer frame

for ni, networktype in enumerate(netdict):
    for si, sigtype in enumerate(sigdict):
        fig.add_subplot(outer[ni*2+si])
        plt.title(networktype+ " " + sigtype) # title for each outer frame
        plt._frameon=False # this should make the unnecessary white frame go away
        inner = gridspec.GridSpecFromSubplotSpec(2, 3, # make 2x3 inner frame
                        subplot_spec=outer[ni*2+si], wspace=0.4, hspace=0.4)
        for ti,tau in enumerate([5.5,12.5]):
            for u, xy_delay in enumerate([0,tau,2*tau]):
                ax = plt.Subplot(fig, inner[ti*3+u])
                ax.plot(np.sin(np.linspace(0,10,0.5))
                ax.set(title=r"$\tau_u={}$".format(xy_delay))
                fig.add_subplot(ax)
plt.show()

Answer 1

只是偶然发现了这一点，因为我不得不做类似的事情。我发现一个简单的解决方案是为外部网格创建另一个子图并简单地关闭它们的轴：

import matplotlib.pyplot as plt
import matplotlib.gridspec as gridspec

fig = plt.figure(figsize=(12, 6))
outer = gridspec.GridSpec(1, 2, wspace=0.2, hspace=0.2)

for i, layer in enumerate(layer_list):
    # create inner plots
    inner = gridspec.GridSpecFromSubplotSpec(2, 2,
                    subplot_spec=outer[i], wspace=0.1, hspace=0.1)
    # set outer titles
    ax = plt.Subplot(fig, outer[i])
    ax.set_title("Layer {}".format(layer))
    ax.axis('off')
    fig.add_subplot(ax)
    for j, filter_pos in enumerate(filter_pos_list):
        # create image plot
        ax = plt.Subplot(fig, inner[j])
        # load image
        img = ...
        ax.imshow(img)
        # set inner title
        ax.set_title("Filter {}".format(filter_pos))
        ax.set_xticks([])
        ax.set_yticks([])
        fig.add_subplot(ax)
fig.show()