在有序表上按最大日期删除重复行

Question

我有一个包含以下数据的示例表

示例表

ID	DATE	NAME
9	2021-04-13 21:39:00.569000	ABC
8	2020-12-17 16:49:17.903000	ABC
7	2020-12-16 16:49:17.903000	ABC
6	2020-06-09 09:55:52.005000	WER
5	2020-06-09 09:55:52.004000	WER
4	2020-06-08 09:48:43.318000	YTG
3	2020-06-05 14:51:42.860000	YTG
2	2020-04-28 13:58:30.972000	YTG
1	2020-04-25 13:58:30.972000	ABC

而且我想为表中的每个不同名称获取它的最大日期，直到找到一个不同的名称。所以结果集一定是这样的

预期输出

ID	DATE	NAME
9	2021-04-13 21:39:00.569000	ABC
6	2020-06-09 09:55:52.005000	WER
4	2020-06-08 09:48:43.318000	YTG
1	2020-04-25 13:58:30.972000	ABC

我尝试了如下的sql查询，没有结果。

select NAME
from
(
  select NAME, max(DATE) - min(DATE) as diff
  from Example_Table
  group by NAME
) ex
order by diff desc;

Answer 1

使用lead():

select t.*
from (select t.*,
             lead(name) over (order by date) as next_name
      from t
     ) t
where next_name is null or next_name <> name;