【发布时间】:2022-08-16 21:27:16
【问题描述】:
我有一个字典列表,我需要从中获取值并创建数据框。我的列表如下所示:
> list_values = [{\'id\': 42,
> \'start_time\': 1660186432206,
> \'update_time\': 1660186432235,
> \'participants\': [{\'object_type\': \'device\',
> \'object_id\': 429496764},
> {\'object_type\': \'device_2\',
> \'object_id\': 429494234},
> {\'object_type\': \'device_3\',
> \'object_id\': 429494123}],
> \'title\':\'Something\'},
> {\'id\': 422,
> \'start_time\': 1623186432206,
> \'update_time\': 1690186432235,
> \'participants\': [{\'object_type\': \'devicedf\',
> \'object_id\': 429496764},
> {\'object_type\': \'device_as\',
> \'object_id\': 429494234},
> {\'object_type\': \'device_ad\',
> \'object_id\': 4294657123}],
> \'title\':\'Something213\'}]
当然,这个列表更大。所以基本上我需要创建一个如下所示的 DF:
id start_time object_id
42 1660186432206 429496764
42 1660186432206 429494234
42 1660186432206 429494123
422 1623186432206 429496764
422 1623186432206 429494234
422 1623186432206 4294657123
我可以通过以下方式获取 ID 和开始时间:
id = [a[\'start_time\'] for a in list_values ]
start_time = [b[\'start_time\'] for b in list_values ]
不幸的是,我无法获得有关 object_id 的信息,并将其与 id 和 start_time 结合起来以创建 DF。你知道我该怎么做吗?
-
您的输入结构是嵌套的。使用
[part[\'object_id\'] for part in a[\'participant\']]访问object_id有什么问题?
标签: python list dataframe dictionary for-loop