【发布时间】：2022-08-03 12:15:38
【问题描述】：
package com.codedecode.demo.entity;
import java.io.Serializable;
import java.util.Collection;
import java.util.Date;
import java.util.HashSet;
import java.util.Set;
import javax.persistence.CascadeType;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.FetchType;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import javax.persistence.JoinColumn;
import javax.persistence.JoinTable;
import javax.persistence.ManyToMany;
import javax.persistence.OneToMany;
import javax.persistence.OneToOne;
import javax.persistence.Table;
import com.fasterxml.jackson.annotation.JsonIgnore;
import lombok.EqualsAndHashCode;
import lombok.Getter;
import lombok.NoArgsConstructor;
import lombok.Setter;
import lombok.ToString;
@Getter
@Setter
@NoArgsConstructor
@Entity
@Table(name = \"users\")
public class User implements Serializable {
/**
*
*/
private static final long serialVersionUID = 1L;
@Id
@GeneratedValue(strategy = GenerationType.AUTO)
private Long id;
@Column(name = \"email\", unique = true, length = 100)
private String email;
@OneToMany(mappedBy = \"user\", cascade = CascadeType.ALL, fetch = FetchType.LAZY)
@EqualsAndHashCode.Exclude
@ToString.Exclude
@JsonIgnore
private Collection<CV> cv;
@OneToMany(mappedBy = \"user\", cascade = CascadeType.ALL, fetch = FetchType.LAZY)
@EqualsAndHashCode.Exclude
@ToString.Exclude
@JsonIgnore
private Collection<JobApplication> jobApplication;
@OneToMany(mappedBy = \"user\", cascade = CascadeType.ALL, fetch = FetchType.LAZY)
@EqualsAndHashCode.Exclude
@ToString.Exclude
@JsonIgnore
private Collection<CurriculumVitae> curriculumVitae;
@OneToMany(mappedBy = \"user\", cascade = CascadeType.ALL, fetch = FetchType.LAZY)
@EqualsAndHashCode.Exclude
@ToString.Exclude
@JsonIgnore
private Collection<CoverLetter> coverLetter;
@ManyToMany(fetch = FetchType.LAZY)
@JoinTable(name = \"users_roles\", joinColumns = @JoinColumn(name = \"user_id\"), inverseJoinColumns = @JoinColumn(name = \"role_id\"))
private Set<Role> roles = new HashSet<>();
@OneToOne(fetch = FetchType.LAZY, optional = false)
@JoinColumn(name = \"address_id\", referencedColumnName = \"id\")
@ToString.Exclude
@JsonIgnore
private Address address;
@Column(name = \"password\")
private String password;
@Column(name = \"birth_date\")
private Date birthDate;
@Column(name = \"name\")
private String name;
@Column(name = \"description\")
private String description;
@Column(name = \"career_goals\")
private String careerGoals;
@Column(name = \"university\")
private String university;
@Column(name = \"rating\")
private String rating;
@Column(name = \"phone\")
private String phone;
@OneToMany(mappedBy = \"user\", cascade = CascadeType.ALL, fetch = FetchType.LAZY)
@EqualsAndHashCode.Exclude
@ToString.Exclude
@JsonIgnore
private Collection<Notification> notifications;
@Column(name = \"maria_status\")
private String mariaStatus;
@OneToMany(mappedBy = \"user\", cascade = CascadeType.ALL, fetch = FetchType.LAZY)
@EqualsAndHashCode.Exclude
@ToString.Exclude
@JsonIgnore
private Collection<Degree> degrees;
@OneToMany(mappedBy = \"user\", cascade = CascadeType.ALL, fetch = FetchType.LAZY)
@EqualsAndHashCode.Exclude
@ToString.Exclude
@JsonIgnore
private Collection<Posting> postings;
@Column(name = \"gender\")
private String gender;
@OneToMany(mappedBy = \"user\", cascade = CascadeType.ALL, fetch = FetchType.LAZY)
@EqualsAndHashCode.Exclude
@ToString.Exclude
@JsonIgnore
private Collection<Language> languages;
@OneToMany(mappedBy = \"user\", cascade = CascadeType.ALL, fetch = FetchType.LAZY)
@EqualsAndHashCode.Exclude
@ToString.Exclude
@JsonIgnore
private Collection<Experience> experiences;
@Column(name = \"taxt_number\")
private Long taxtNumber;
@Column(name = \"images\")
private String images;
@Column(name = \"candidate_cv\")
private String candidateCV;
@OneToOne(fetch = FetchType.LAZY, cascade = CascadeType.ALL)
@JoinColumn(name = \"desired_job_id\", referencedColumnName = \"id\")
private DesiredJob desiredJob;
@OneToMany(mappedBy = \"candidate\", cascade = CascadeType.ALL, fetch = FetchType.LAZY)
@EqualsAndHashCode.Exclude
@ToString.Exclude
@JsonIgnore
private Collection<Message> candidateMessage;
@OneToMany(mappedBy = \"recruiter\", cascade = CascadeType.ALL, fetch = FetchType.LAZY)
@EqualsAndHashCode.Exclude
@ToString.Exclude
@JsonIgnore
private Collection<Message> recruiterMessage;
// @OneToOne(fetch = FetchType.LAZY, optional = false) // @JoinColumn(name = \"candidate_profile_save_id\", referencedColumnName = \"id\") @OneToOne(mappedBy = \"user\", cascade = CascadeType.ALL, fetch = FetchType.LAZY) @ToString.Exclude @JsonIgnore private CandidateProfileSaved candidateProfileSaved;
@OneToMany(mappedBy = \"user\", cascade = CascadeType.ALL, fetch = FetchType.LAZY)
@ToString.Exclude
@JsonIgnore
private Collection<SavedJob> savedJob;
@OneToMany(mappedBy = \"user\", cascade = CascadeType.ALL, fetch = FetchType.LAZY)
@EqualsAndHashCode.Exclude
@ToString.Exclude
@JsonIgnore
private Collection<AppliedJob> appliedJob;
public User(Long id, String email) {
this.id = id;
this.email = email;
}
@Override
public String toString() {
StringBuilder builder = new StringBuilder();
builder.append(\"User [id=\");
builder.append(id);
builder.append(\", email=\");
builder.append(email);
builder.append(\", address=\");
builder.append(address);
builder.append(\", password=\");
builder.append(password);
builder.append(\", name=\");
builder.append(name);
builder.append(\"]\");
return builder.toString();
}
}
我不知道为什么当我尝试从邮递员调用 api 将更多用户插入数据库时，我有一个错误是：\“违反唯一键约束 \'UK_hbvhqvjgmhd5omxyo67ynvbyp\'。无法在对象 \'dbo 中插入重复键。 users\'。重复的键值为 (1)。\"
为什么用户的主键不递增？
标签： sql-server spring-boot hibernate spring-data-jpa orm