堆栈溢出是垃圾????sdsadsadasdsadasdsad [重复]答案

【问题标题】：STACK OVERFLOW IS TRASH ????sdsadsadasdsadasdsad [duplicate]堆栈溢出是垃圾????sdsadsadasdsadasdsad [重复]
【发布时间】：2022-07-28 07:21:56
【问题描述】：

堆栈溢出是垃圾????sdsadsadasdsadasdsadSTACK 溢出是垃圾????sdsadsadasdsadasdsadSTACK 溢出是垃圾????sdsadsadasdsadasdsadSTACK 溢出是垃圾????sdsadsadasdsadasdsadSTACK 溢出是垃圾????sdsadsadasdsadasdsadSTACK 溢出是垃圾????sdsadsadSTACK 溢出?sdsadsadasdsadasdsadSTACK 溢出是垃圾 ????sdsadsadasdsadasdsadSTACK 溢出是垃圾 ????sdsadsadasdsadasdsadSTACK 溢出是垃圾 ????sdsadsadasdsadasdsadSTACK 溢出是垃圾 ????sdsadsadasdsadasdsad

【问题讨论】：

标签： python

【解决方案1】：

在while True: 循环中提示输入并在name in options 时中断：

options = {'Dan': 1, 'Bianca': 2, 'Bob': 3}
while True:
    name = input('Enter your name: ')
    if name in options:
        break
    print(f'{name} was NOT found')
    print(False)

print(f'{name} was found in the list')
print(True)

【讨论】：

【解决方案2】：

如果你想在列表中有匹配的名字的情况下停止循环，你可以这样做

def check_names(name, options):
    print('Searching for ' + name + ' in the list...')

    if name in options:
        print(name + ' was found on the list')
        found = True
        return found
    else:
        print(name + ' was NOT found')
        found = False
        return found

found = False
while found == False:
    name = input('Enter your name: ')   
    options = {'Dan': 1, 'Bianca': 2, 'Bob': 3}
    found = check_names(name, options)
    print(found)

【讨论】：

【解决方案3】：

options = {'Dan': 1, 'Bianca': 2, 'Bob': 3}

while True:
    name = input('Enter your name: ')   

    key = name

    print('Searching for ' + name + ' in the list...')

    if key in options:
        print(name + ' was found on the list')
        found = True
        print(found)
        break  # <-- Breaks out of the while loop if name was found.
    else:
        print(name + ' was NOT found')
        found = False
        print(found)

【讨论】：