显示准确的时间

Question

我有以下问题

SELECT
    CASE 
        WHEN CS.StartTime > CURRENT_TIMESTAMP THEN 'STARTING LATER'
        WHEN x.timing <  30 THEN 'A LITTLE LATE' 
        WHEN x.timing >= 30 THEN 'VERY LATE'
        ELSE 'Unknown Status'
    END as RefreshStartStatus,
    CASE WHEN CS.StartTime <= CURRENT_TIMESTAMP THEN CONCAT(x.timing ', min(s) late') END as info
FROM #CSTempTable CS
LEFT OUTER JOIN #SubscriptionAggTempTable SA ON SA.SubscriptionID = CS.SubscriptionID
CROSS APPLY (VALUES (DATEDIFF(MINUTE, CS.StartTime, SA.TodayFirstRunTime))) as x(timing)

示例结果：

RefreshStartStatus  info
A LITTLE LATE       0 min(s) late
STARTING LATER      NULL
A LITTLE LATE       9 min(s) late
A LITTLE LATE       0 min(s) late
STARTING LATER      NULL
A LITTLE LATE       0 min(s) late
VERY LATE           46 min(s) late
Unknown Status      min(s) late
A LITTLE LATE       0 min(s) late

这很好，但 0 有点误导。可能是毫秒级的差异导致刷新有点晚，那么我怎样才能让这个显示准确的时间呢？

例如

A LITTLE LATE       2 sec(s) late
A LITTLE LATE       1 min(s) late

或者如果这很复杂，那么

A LITTLE LATE       0.03 min(s) late
A LITTLE LATE       1 min(s) late

注意：2 秒等于 0.0333 分钟

Answer 1

您可以将其用于低于 60 秒的顺从和高于 60 秒的顺从

 SELECT
CASE 
    WHEN CS.StartTime > CURRENT_TIMESTAMP THEN 'STARTING LATER'
    WHEN x.timing <  1800*1000 THEN 'A LITTLE LATE' 
    WHEN x.timing >= 1800*1000 THEN 'VERY LATE'
    ELSE 'Unknown Status'
END as RefreshStartStatus,
CASE WHEN CS.StartTime <= CURRENT_TIMESTAMP THEN 
    CASE WHEN x.timing < 1000 THEN
        CONCAT(x.timing ,', millisecond(s) late')
    WHEN x.timing < 60000 THEN
        CONCAT(x.timing/1000 ,', Second(s) late')
    ELSE
        CONCAT(x.timing/60000 ,', min(s) late')
    END
ELSE
CASE WHEN ABS(x.timing) < 1000 THEN
        CONCAT(ABS(x.timing) ,', millisecond(s) until it starts')
    WHEN ABS(x.timing) < 60000 THEN
        CONCAT(ABS(x.timing)/1000 ,', Second(s) until it starts')
    ELSE
        CONCAT(ABS(x.timing)/60000 ,', min(s) until it starts')
    END
END as info
FROM #CSTempTable CS
LEFT OUTER JOIN #SubscriptionAggTempTable SA ON SA.SubscriptionID = CS.SubscriptionID
CROSS APPLY (VALUES (DATEDIFF(MILLISECOND, CS.StartTime, SA.TodayFirstRunTime))) as x(timing)

我创建两个临时表并测试结果：

CREATE TABLE #CSTempTable
(
StartTime dateTime,
SubscriptionID int
)
CREATE TABLE #SubscriptionAggTempTable
(
SubscriptionID int,
TodayFirstRunTime datetime
)

并在表格中插入两行

 INSERT INTO #CSTempTable
VALUES (DATEADD(SECOND,-10,GETDATE()),1)

INSERT INTO #CSTempTable
VALUES (DATEADD(SECOND,10,GETDATE()),1)

INSERT INTO #CSTempTable
VALUES (DATEADD(MILLISECOND,-150,GETDATE()),1)

INSERT INTO #CSTempTable
VALUES (DATEADD(SECOND,-170,GETDATE()),1)

INSERT INTO #SubscriptionAggTempTable
VALUES (1,GETDATE())

运行后查询结果为：

Answer 2

然后计算以秒为单位的差异，然后进行数学运算：

SELECT
    CASE 
        WHEN CS.StartTime > CURRENT_TIMESTAMP THEN 'STARTING LATER'
        WHEN x.timing <  30 * 60 THEN 'A LITTLE LATE' 
        WHEN x.timing >= 30 * 60 THEN 'VERY LATE'
        ELSE 'Unknown Status'
    END as RefreshStartStatus,
    CASE WHEN CS.StartTime <= CURRENT_TIMESTAMP THEN CONCAT(x.timing / 60.0,  ' min(s) late') END as info
FROM #CSTempTable CS
LEFT OUTER JOIN #SubscriptionAggTempTable SA ON SA.SubscriptionID = CS.SubscriptionID
CROSS APPLY (VALUES (DATEDIFF(SECOND, CS.StartTime, SA.TodayFirstRunTime))) as x(timing)

您可能希望格式化、舍入或截断除法的结果，以防它不能给出精确的结果，例如：

CONCAT(CONVERT(DECIMAL(10, 2), x.timing / 60.0),  ' min(s) late')

或者，如果您想仅显示有效的十进制数字，请使用FORMAT()：

CONCAT(FORMAT(x.timing / 60.0, '0.##'),  ' min(s) late')