使用行计数消除重复值

Question

我使用行数来返回匹配 1 或 2 的值。我需要保持所有值等于 2。但是，根据我正在尝试的列名，一些行数为 1 的值是相同的过滤。我正在寻找的是一种保留计数为 2 的行但仅在行计数为 2 时才排除计数为 1 的行的方法。在下面的示例中，我返回相同的 salesorder ID 为 528886，但想排除该行，因为它有第 2 行。

查询：

select * from (
    select *, ROW_NUMBER() over (partition by SalesOrderPostedID
    Order By SalesOrderPostedID) as RowNumber
    from cte5) c
    Where SalesOrderPostedID=528886
    and c.RowNumber=1
    Union all
    select * from (
    select *, ROW_NUMBER() over (partition by SalesOrderPostedID
    Order By SalesOrderPostedID) as RowNumber
    from cte5) c
    Where SalesOrderPostedID=528886
    and c.RowNumber=2

我已附上结果。

---

Gorgon 提供的解决方案稍作修改。下面的查询返回计数为一或二的所有行或计数仅为一的任何行。

选择 c.* 从（选择 cte5.， row_number() over（按 SalesOrderPostedID 分区 按销售订购OrderPostedID ) 作为行号， count() 超过（按 SalesOrderPostedID 分区）为 cnt 从 cte5 ） C 其中（行号 = 2 或 cnt = 1);

Answer 1

你为什么不这样做？

select c.*
from (select c.*, 
             row_number() over (partition by SalesOrderPostedID
                                Order By SalesOrderPostedID
                               ) as RowNumber
     from cte5
    ) c
where SalesOrderPostedID = 528886 and c.RowNumber <= 2;

如果您只想要成对的行，请使用：

select c.*
from (select c.*, 
             row_number() over (partition by SalesOrderPostedID
                                Order By SalesOrderPostedID
                               ) as RowNumber,
             count(*) over (partition by SalesOrderPostedID) as cnt
     from cte5
    ) c
where SalesOrderPostedID = 528886 and RowNumber <= 2 and
      cnt >= 2;