MIPS 将十进制转换为二进制运行错误

Question

有人可以查看我的代码，看看是否有任何错误导致我出错？

**我收到的错误：**spim:(parser) 标签是在文件 C:/Users/Desktop/test5.asm main 的第 8 行第二次定义的： ^

错误是试图说我的代码中有 2 个“主”字吗？我尝试删除其中一个..但失败了。

.data
msg1: .asciiz "Please insert value (A > 0) : "
msg2: .asciiz "Please insert the number system B you want to 
convert to (2<=B<=10): "
#Above sting must be in one line
msg3: .asciiz "\nResult : "
.text
.globl main
main:
addi $s0,$zero,2
addi $s1,$zero,10
getA:

li $v0,4
la $a0,msg1
syscall
li $v0,5
syscall
blt $v0,$zero,getA

move $t0,$v0
getB:

li $v0,4
la $a0,msg2
syscall
li $v0,5
syscall
blt $v0,$s0,getB
bgt $v0,$s1,getB

add $t1,$zero,$v0

li $v0,4
la $a0,msg3
syscall

add $a0,$zero,$t0
add $a1,$zero,$t1

jal convert

li $v0,10
syscall

convert:
#a0=A
#a1=B

addi $sp,$sp,-16

sw $s3,12($sp) #counter,used to know
#how many times we will pop from stack
sw $s0,8($sp) #A
sw $s1,4($sp) #B
sw $ra,0($sp)

add $s0,$zero,$a0
add $s1,$zero,$a1

beqz $s0,end

div $t4,$s0,$s1 #t4=A/B
rem $t3,$s0,$s1 #t3=A%B
add $sp,$sp,-4
sw $t3,0($sp) #save t3

add $a0,$zero,$t4 #pass A/B
add $a1,$zero,$s1 #pass B
addi $s3,$s3,1
jal convert        #call convert

end:

lw $ra,0($sp)
lw $s1,4($sp)
lw $s0,8($sp)
lw $s3,12($sp)
beqz $s3,done
lw $a0,16($sp)
li $v0,1
syscall
done: 
addi $sp,$sp,20
jr $ra   #return

Answer 1

已解决.TQ

原来SPIM编译器搞砸了