如何判断 X 和 Y 坐标是否在我的按钮内？

Question

我费了很大的力气才使位图覆盖在屏幕上。我也可以获得触摸输入，但是它可以在屏幕上的任何地方获得触摸输入。

我想知道如何检查触摸是否在屏幕上可见的位图上。

服务和视图类如下。想了又想，还是想不出办法:(

package <package>;

import android.app.NotificationManager;
import android.app.PendingIntent;
import android.app.Service;
import android.content.Context;
import android.content.Intent;
import android.graphics.Bitmap;
import android.graphics.BitmapFactory;
import android.graphics.Canvas;
import android.graphics.Color;
import android.graphics.Paint;
import android.graphics.PixelFormat;
import android.graphics.Rect;
import android.os.IBinder;
import android.support.v4.app.NotificationCompat;
import android.view.Gravity;
import android.view.MotionEvent;
import android.view.ViewGroup;
import android.view.WindowManager;
import android.widget.Toast;

public class MyService extends Service {
    ButtonView mView;
    Bitmap bit;

    @Override
    public IBinder onBind(Intent intent) {
        return null;
    }

    @Override
    public void onCreate() {
        super.onCreate();

        bit = BitmapFactory.decodeResource(getResources(), R.drawable.button);

        NotificationCompat.Builder builder = new NotificationCompat.Builder(
                this);
        builder.setContentTitle("Ingress Tools Running");
        builder.setContentText("Click to stop Ingress Tools");
        builder.setSmallIcon(R.drawable.ic_launcher);
        builder.setContentIntent(PendingIntent.getActivity(this, 0, new Intent(
                this, StopActivity.class), 0));
        NotificationManager manager = (NotificationManager) getSystemService(Context.NOTIFICATION_SERVICE);
        manager.notify(1, builder.build());

        mView = new ButtonView(this, bit);
        WindowManager.LayoutParams params = new WindowManager.LayoutParams(
                WindowManager.LayoutParams.FILL_PARENT,
                WindowManager.LayoutParams.FILL_PARENT,
                WindowManager.LayoutParams.TYPE_PHONE,
                WindowManager.LayoutParams.FLAG_NOT_FOCUSABLE
                        | WindowManager.LayoutParams.FLAG_NOT_TOUCH_MODAL
                        | WindowManager.LayoutParams.FLAG_WATCH_OUTSIDE_TOUCH,
                PixelFormat.TRANSLUCENT);
        params.gravity = Gravity.RIGHT;
        params.setTitle("Load Average");
        WindowManager wm = (WindowManager) getSystemService(WINDOW_SERVICE);
        wm.addView(mView, params);

    }

    @Override
    public void onDestroy() {
        super.onDestroy();
        Toast.makeText(getBaseContext(), "onDestroy", Toast.LENGTH_LONG).show();
        if (mView != null) {
            ((WindowManager) getSystemService(WINDOW_SERVICE))
                    .removeView(mView);
            mView = null;
        }
    }
}

class ButtonView extends ViewGroup {
    private Paint mLoadPaint;
    private Rect r;
    private Bitmap bit;

    public ButtonView(Context context, Bitmap bit) {
        super(context);
        Toast.makeText(context, "HUDView", Toast.LENGTH_LONG).show();

        mLoadPaint = new Paint();
        mLoadPaint.setAntiAlias(true);
        mLoadPaint.setTextSize(10);
        mLoadPaint.setARGB(255, 255, 0, 0);
        r = new Rect();
        r.set(380, 134, 468, 213);
        this.bit = bit;
    }

    @Override
    protected void onDraw(Canvas canvas) {
        super.onDraw(canvas);
        //canvas.drawColor(Color.BLACK);

        canvas.drawBitmap(bit, 100, 100, null);
    }

    @Override
    protected void onLayout(boolean arg0, int arg1, int arg2, int arg3, int arg4) {
    }

    @Override
    public boolean onTouchEvent(MotionEvent event) {

        int area = bit.getWidth() * bit.getHeight();


        //if (event.getY() <= maxY && event.getX() <= maxX) {
            Toast.makeText(getContext(), "Open tools: ", Toast.LENGTH_LONG)
                    .show();

        //}
        return true;

    }
}

Answer 1

这适用于任何视图

@Override
    public boolean dispatchTouchEvent(MotionEvent event) {

            if (event.getAction() == MotionEvent.ACTION_UP) {
                if (inViewInBounds(myButtonView, (int) event.getRawX(), (int) event.getRawY())) {
                    // User moved outside bounds
                    Log.e("dispatchTouchEvent", "you touched inside button");
                } else {
                    Log.e("dispatchTouchEvent", "you touched outside button");
                }

        }
        return super.dispatchTouchEvent(event);
    }

 Rect outRect = new Rect();
    int[] location = new int[2];


 private boolean inViewInBounds(View view, int x, int y) {
        view.getDrawingRect(outRect);
        view.getLocationOnScreen(location);
        outRect.offset(location[0], location[1]);
        return outRect.contains(x, y);
    }

Answer 2

考虑直接使用FrameLayout（或ViewGroup 的任何其他子类）而不是ViewGroup。因为您当前对onLayout 方法的实现不正确，这将导致您在显示子视图时出现问题。

现在，更接近您的问题。您应该初始化Rect 并只存储Bitmap 的左、上、右和下位置。如我所见，目前您已初始化 r 变量，但没有在任何地方使用它。

所以，你可以这样初始化它：

r = new Rect(100, 100, 100 + bit.getWidth(), 100 + bit.getHeight());

现在您可以在onTouchEvent 中查看：

r.contains((int) event.getX(), (int) event.getY());

Answer 3

Rect rect = new Rect(); 
getHitRect(rect);
if (rect.contains((int) event.getX(), (int) event.getY())) {}

您可以使用 getHitRect(Rect)。它返回父坐标中的 Hit 矩形。 Here文档

Answer 4

在您要检查的按钮上使用带有方法if(r.contains(x, y)) 的if 语句。当 x 和 y 点在矩形 r 内时，此方法将返回 true。您还可以在该类中创建公共方法，以便您可以在 ButtonView 类之外使用按钮对象引用访问它。

Answer 5

// We assume MotionEvent is from the direct View parent so we are in the same co-ordindate space
fun View.isWithinBounds(event: MotionEvent): Boolean {
    val rect = Rect(x.roundToInt(), y.roundToInt(), (x + width).roundToInt(), (y + height).roundToInt())
    return rect.contains(event.x.roundToInt(), event.y.roundToInt())
}

Answer 6

当“触摸事件”发生时，它会遍历所有视图的树。 F.e.如果你有线性布局和 ImageView 并且用户在 ImageView 上触摸屏幕，则触摸事件拦截，首先它将在 LinearLayour 处处理，然后在 ImageView 处处理。

如果您想阻止事件 f.e.在位图上，那么您应该覆盖位图的 onTouchEvent 并返回真值。这意味着你处理了这个事件，它不适用于 LinearLayout。

image.setOnTouchListener( new View.OnTouchListener() {
            @Override
            public boolean onTouch(View view, MotionEvent motionEvent) {
                return true;  // attentively read documentation for onTouc interface
            }
        });