SELECT
id AS kid,
NAME,

IF (t1.kpi, t1.kpi, 0) AS kpi,
t1.sort,
STATUS,
t1.kpi_id
FROM
form_kpi_name
LEFT JOIN (
SELECT
kpi_id AS i,
kpi,
sort,
username,
id AS kpi_id
FROM
faw_form_kpi
WHERE
username = '123'
) AS t1 ON form_kpi_name.id = t1.i
WHERE
form_kpi_name.type = 0

如果是取差集 可以在 加 t1表或form_kpi_name 表的的关联id is null  如:where t1.i is null;

相关文章:

  • 2022-12-23
  • 2021-11-28
  • 2022-12-23
  • 2022-12-23
  • 2022-12-23
  • 2022-12-23
  • 2021-06-18
猜你喜欢
  • 2023-02-07
  • 2022-12-23
  • 2022-12-23
  • 2022-12-23
  • 2022-12-23
  • 2022-12-23
  • 2021-10-18
相关资源
相似解决方案