SQL 获取用户连续签到天数

DECLARE @days INT -- 签到天数
SET @days=0
DECLARE @curr_day DATETIME -- 当前日期
SET @curr_day=DATEDIFF(DD,-1,GETDATE()) -- 默认昨天
DECLARE @todaySign BIT -- 今日是否签到
SET @todaySign=0
WHILE EXISTS(SELECT NULL FROM [Table_Sign] WHERE [UserID] = 1000120 AND DATEDIFF(DD,AddTime,@curr_day) = 1) -- 如果当前天的前一天有签到记录
BEGIN
　　SET @days=@days+1
　　SET @curr_day=DATEDIFF(DD,-1,@curr_day)
END
IF((SELECT 1 FROM [Table_Sign] WHERE [UserID] = 1000120 AND CONVERT(varchar(10),[AddTime],23) = CONVERT(varchar(10),GETDATE(),23))IS NOT NULL) -- 今日是否完成签到
BEGIN
　　SET @days=@days+1
　　SET @todaySign=1
END
IF(@days>7) -- 是否为一个周期
BEGIN
　　IF(@days%7=0)
　　BEGIN
　　　　SET @days=7
　　END
　　ELSE
　　BEGIN
　　　　SET @days=@days%7
　　END
END
SELECT TOP 1 @days AS ContinueDays,@todaySign AS TodaySign FROM [Table_Sign] WHERE [UserID] = 1000120