方法1:

        string m_Str = "1984-04-04";
        int m_Y1 = DateTime.Parse(m_Str).Year;
        int m_Y2 = DateTime.Now.Year;
        int m_Age = m_Y2 - m_Y1;
        Response.Write(m_Age);

方法2:

      如果你将日期格式化为yyyymmdd,并且从当前日子减去生日,最后去除4个数字,就得到年龄了:)
      我相信这样的方法可以用任何语言实现:

     20080814-19800703=280111

     去除最后4位 = 28.

 

    int now =int.Parse(DateTime.Today.ToString("yyyyMMdd"));

int dob =int.Parse(dateDOB.ToString("yyyyMMdd"));

string dif =(now - dob).ToString();

string age ="0";

if(dif.Length>4) age = dif.Substring(0, dif.Length-4);


方法3:
DateTime now =DateTime.Today;

int age = now.Year- bday.Year;

if(bday > now.AddYears(-age)) age--;
 
 

相关文章:

  • 2021-05-26
  • 2022-12-23
  • 2022-12-23
  • 2022-12-23
  • 2022-12-23
  • 2022-12-23
  • 2022-12-23
  • 2021-11-21
猜你喜欢
  • 2022-01-16
  • 2021-11-30
  • 2021-11-26
  • 2021-06-15
  • 2021-11-30
  • 2021-09-23
相关资源
相似解决方案